You would like to develop a new galvanic cell and decide to use two very toxic electrode materials, mercury and cadmium. But because they are toxic, you decide to use a low concentration of each material. Cd I Cd²+ (0.20M) 1. The ◆ electrode is the anode, and the 2. Write the two half equations and the balanced overall equation: The half reaction for chromium (hint written as a reduction): The half reaction for mercury (hint written as a reduction): Overall reaction balanced equation is: Eºcell = Ecell = ◆ Has the voltage improved? is the cathode + 3. What is the Eºcell and the Ecell of this reaction? Have you improved your battery by reducing the concentration? Hint: use the Nerst equation E = E° -RT/nF x(InQ) || Hg²+ (0.10M) I Hg
You would like to develop a new galvanic cell and decide to use two very toxic electrode materials, mercury and cadmium. But because they are toxic, you decide to use a low concentration of each material. Cd I Cd²+ (0.20M) 1. The ◆ electrode is the anode, and the 2. Write the two half equations and the balanced overall equation: The half reaction for chromium (hint written as a reduction): The half reaction for mercury (hint written as a reduction): Overall reaction balanced equation is: Eºcell = Ecell = ◆ Has the voltage improved? is the cathode + 3. What is the Eºcell and the Ecell of this reaction? Have you improved your battery by reducing the concentration? Hint: use the Nerst equation E = E° -RT/nF x(InQ) || Hg²+ (0.10M) I Hg
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![You would like to develop a new galvanic cell and decide to use two very toxic electrode materials, mercury and cadmium.
But because they are toxic, you decide to use a low concentration of each material.
Cd I
Cd²+ (0.20M)
1. The
electrode is the anode, and the
2. Write the two half equations and the balanced overall equation:
The half reaction for chromium (hint written as a reduction):
The half reaction for mercury (hint written as a reduction):
Overall reaction balanced equation is:
Eºcell
+
Ecell =
◆ is the cathode
Has the voltage improved? ◆
||
3. What is the Eºcell and the Ecell of this reaction? Have you improved your battery by reducing the concentration? Hint: use the Nerst equation E = E° -RT/nF x(InQ)
Hg²+ (0.10M) |
Hg](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1f77e9fc-681c-4428-a69c-c68359a448ea%2F7e7e0142-a66e-4644-a717-a103b7f521d0%2F2lsbt48_processed.png&w=3840&q=75)
Transcribed Image Text:You would like to develop a new galvanic cell and decide to use two very toxic electrode materials, mercury and cadmium.
But because they are toxic, you decide to use a low concentration of each material.
Cd I
Cd²+ (0.20M)
1. The
electrode is the anode, and the
2. Write the two half equations and the balanced overall equation:
The half reaction for chromium (hint written as a reduction):
The half reaction for mercury (hint written as a reduction):
Overall reaction balanced equation is:
Eºcell
+
Ecell =
◆ is the cathode
Has the voltage improved? ◆
||
3. What is the Eºcell and the Ecell of this reaction? Have you improved your battery by reducing the concentration? Hint: use the Nerst equation E = E° -RT/nF x(InQ)
Hg²+ (0.10M) |
Hg
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