You wish to test the following claim (Ha) at a significance level of a = 0.05. Ho:p = 0.26 Ha:p + 0.26 а You obtain a sample of size n = 568 in which there are 179 successful observations. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value : %3D The p-value is... less than (or equal to) a greater than a
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- 1.Determine the test statistic. (Round to three decimal places as needed.) 2.Determine the P-value of the test statistic. (Round to four decimal places as needed.) 3.Use a 0.05 significance level to test the claim that the amount of smoking is independent of seat belt use.In a study, people were observed for about 10 seconds in public places, such as malls and restaurants, to determine whether they smiled during the randomly chosen 10-second interval. The table shows the results for comparing males and females. Complete parts a through c below. The percentage of women who were smiling in the sample was 50.86 %. (Round to two decimal places as needed.) Compare the sample percentages. The percentage of people who were smiling was greater for the women. a. Find and compare the sample percentages of men who were smiling and women who were smiling. The percentage of men who were smiling in the sample was 48.06 %. (Round to two decimal places as needed.) OA. Ho: P₁ P2 HA: P₁ P₂ Smile No Smile b. Treat this as though it was a random sample, and test whether there are differences in the proportion of men and the proportion of women who smile. Use a significance level of 0.05. O D. Ho: P₁ P2 HA: P₁ = P₂ Male 3243 3505 Determine the hypotheses for this test. Let…I cannot find the test statistic for the image of the problem
- Use technology to help you test the claim about the population mean, µ, at the given level of significance, a, using the given sample statistics. Assume the population is normally distr Claim: µs 1270; a = 0.06; o = 202.73. Sample statistics: x = 1286.71, n = 300 Identify the null and alternative hypotheses. Choose the correct answer below. A. Ho:H2 1270 O B. Ho: Hs 1286.71 HaiH>1286.71 Hai H 1286.71 O D. Ho: H> 1270 HaiHS 1286.71 Ha:HS 1270 E. Hn: H2 1286.71Use technology to help you test the claim about the population mean, p, at the given level of significance, a, using the given sample statistics. Assume the population i: normally distributed. Claim: u> 1250; a = 0.05; o = 212.17. Sample statistics: x= 1268.48, n= 200 Identify the null and alternative hypotheses. Choose the correct answer below. O A. Ho us 1268.48 H p> 1268 48 O B. Ho: µ2 1268.48 H3 p 1250 H us 1250 O D. Ho: µ> 1268.48 H, us 1268.48 O E. Ho us 1250 H >1250 OF. Ho H2 1250 H p< 1250 Calculate the standardized test statistic. The standardized test statistic is (Round to two decimal places as needed.)How Much Do You Read? ~ A nation-wide survey conducted in 2019 asked a random sample of US adults, "During the past 12 months, about how many books did you read either all or part of the way through? Please include any print, electronic, or audiobooks you may have read or listened to." The survey results reported the mean number of books read to be 15. 39 Kelly is a library science major and wonders if adults who have a library card report reading more books in a year than the nationally reported mean. She obtains a random sample of 18 adults with a library card from her community library and asks them the same survey question. From her results she calculates a sample mean of 16.7 and a standard deviation of 4.0441.
- You wish to test the following daim (Ha) at a significance level of a = 0.001. H.:P1 P2 You obtain a sample from the first population with 268 successes and 44 failures. You obtain a sample from the second population with 558 successes and 147 failures. test statistic = [three decimal accuracy] p-value = [four decimal accuracy] The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null hypothesis fail to reject the null hypothesis As such, the final condusion is that... O There is sufficient evidence to support that the first population proportion is greater than the second population proportion. There is not sufficient evidence to support that the first population proportion is greater than the second population proportion.You wish to test the following claim (Ha) at a significance level of a = 0.02. H.:p = 0.78 Ha:p > 0.78 You obtain a sample of size n = 654 in which there are 533 successful observations. What is the critical value for this test? (Report answer accurate to three decimal places.) critical value What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic The test statistic is... in the critical region not in the critical region This test statistic leads to a decision to... reject the null hypothesis accept the null hypothesis fail to reject the null hypothesis As such, the final conclusion is that... There is enough evidence to show that the population proportion is not greater than 0.78. There is not enough evidence to showthat the population proportion is not greater than 0.78. There is enough evidence to show that that the population proportion is greater than 0.78. There is not enough evidence to show that the population proportion is…2. Brand of Smartphone Male A 43 34 48 A. What is the value for the degrees of freedom? B. If the expected number of males with smartphone brand B is 32.5, what is the chi-square component? c. If the test statistic (chi-square) = 6.40, then the p-value = D. If the significance level was 0.05, should the researcher reject or fail to reject the null?
- A sample of 63 stocks traded on the NYSE that day showed that 22 went up. You are conducting a study to see if the proportion of stocks that went up is significantly more than 0.3. You use a significance level of a = 0.05. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a Ogreater than a This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... OThere is sufficient evidence to warrant rejection of the claim that the proportion of stocks that went up is more than 0.3. O There is not sufficient evidence to warrant rejection of the claim that the proportion of stocks that went up is more than 0.3. The sample data support the claim that the proportion of stocks that went up is more than 0.3. There is not…I'LL LEAVE A LIKE IF CORRECT.TYPart 1: Hypothesis Test for the Mean- Manual Tasks• Define your concern of interest drawing upon your variables in your dataset.• Conceptualize your null and alternate hypotheses based on your testing concept.a. Apply 1 one-sided test (upper-tail or lower-tail) and 1 two-sided test concepts for the mean with unknown population standard deviation (�) at 1%, 5%, or 10% levels of significance (choose one of them for each test) by stating the appropriate decision rule. b. Calculate p-value for each of your tests and perform testing for your same hypotheses with p-value solution. Comment on how p-value changes for 1%, 5%, and 10% significance levels (for all three).**Here in order to apply normal distribution approximation, it would be better if you choose your sample size greater than 100 (n>100).c. Make a confidence interval estimation for the population mean with unknown variancebased on 90%, 95% and 99% confidence levels and make interpretations for all three. DATASET:…