Please can someone help with the questions. Not sure of my answers, I m stuck. You wish to test the following claim at a significance level of a = 0.01.Ho:µ = 67.5H1:µ < 67.5You believe the population is normally distributed, but you do not know the standard deviation. You obtaina sample of size 107 with mean 63.3 and a standard deviation of 20.8.What is the test statistic for this sample? (Report answer accurate to 3 decimal places.)What is the p-value for this sample? (Report answer accurate to 4.decimal places.)This test statistic leads to a decision toO reject the nullO accept the nullO fail to reject the nullAs such, the final conclusion is thatO there is sufficient evidence to conclude that the population mean is equal to 67.5.O there is not sufficient evidence to conclude that the population mean is equal to 67.5.O there is sufficient evidence to conclude that the population mean is less than 67.5.O there is not sufficient evidence to conclude that the population mean is less than 67,5.Submit QuestiondtvMacBook Air80888DIIDDF2F3F4F5F6F7FBF9@2$234WE* 00< COS LOW # You are conducting a study to see if the probability of a true negative on a test for a certain cancer issignificantly different from 0.12. You use a significance level of a = 0.10.Ho:p = 0.12H1:p # 0.12You obtain a sample of size 295 in which there are 20 successes.What is the test statistic for this sample? (Report answer accurate to 3 decimal places.)What is the p-value for this sample? (Report answer accurate to 4 decimal places.)This test statistic leads to a decision toO reject the nullO accept the nullO fail to reject the nullAs such, the final conclusion is thatO there is sufficient evidence to conclude that the probability of a true negative on a test for a certaincancer is different from 0.12.O there is not sufficient evidence to conclude that the probability of a true negative on a test for acertain cancer is different from 0.12.O there is sufficient evidence to conclude that the probability of a true negative on a test for a certaincancer is equal to 0.12.O there is not sufficient evidence to conclude that the probability of a true negative on a test for acertain cancer is equal to 0.12.Submit Question14tvMacBook Air888F4DIIF2F3F5F6F7FBF9@2324&234WER60* 00A LO

Note: According to our guidelines we can answer only first question. Kindly repost the remaining question for which you need answer.p-value: The degrees of freedom is 106 (=n–1). Using Excel formula “=T.DIST(-2.089,106,TRUE)”, the p-value is obtained as 0.0196. Decision: Here, p-value is greater than 0.01. Thus, the test statistic leads to a conclusion: fail to reject the null. Conclusion: As such, the final conclusion is that: there is not sufficient evidence to conclude that the population mean is less than 67.5.