You wish to find the enthalpy for the reaction 6 Gel: (s) + 14 NH.l (s) → 3 Ge:H« (I) + 7 N: (g) + 38 HI (g) Given the following equations Equation 1: 2 Ge (s) + 3 H2 (g) → Ge:Hs (1) AH = 137.3 kJ/mol Equation 2: Ge (s) + 4 HI (g) → Gel. (s) + 2 H2(g) AH = -247.8 kJ/mol Equation 3: 2 NH.l (s) → N: (g) + 2 HÌ (g) + 3 H:(g) AH = 455.8 kJ/mol What would be the enthalpy change, in kJ/mol, for 6 Ge (s) + 9 H2 (g) - 3 Ge:Hs (1)?
You wish to find the enthalpy for the reaction 6 Gel: (s) + 14 NH.l (s) → 3 Ge:H« (I) + 7 N: (g) + 38 HI (g) Given the following equations Equation 1: 2 Ge (s) + 3 H2 (g) → Ge:Hs (1) AH = 137.3 kJ/mol Equation 2: Ge (s) + 4 HI (g) → Gel. (s) + 2 H2(g) AH = -247.8 kJ/mol Equation 3: 2 NH.l (s) → N: (g) + 2 HÌ (g) + 3 H:(g) AH = 455.8 kJ/mol What would be the enthalpy change, in kJ/mol, for 6 Ge (s) + 9 H2 (g) - 3 Ge:Hs (1)?
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You wish to find the enthalpy for the reaction
6 Gela (s) + 14 NH:1 (s) → 3 Ge:Ho (1) + 7 N2 (g) + 38 HI (g)
Given the following equations
Equation 1: 2 Ge (s) + 3 H2 (g) → Ge:Ho (I) AH = 137.3 kJ/mol
Equation 2: Ge (s) + 4 HI (g) → Gela (s) + 2 H2(g) AH = -247.8 kJ/mol
Equation 3: 2 NH4I (s) → N2 (g) + 2 HI (g) + 3 H2(g) AH = 455.8 kJ/mol
-6144 kJ/mol
1
What would be the enthalpy change, in kJ/mol, for 6 Ge (s) + 9 H2 (g)
→ 3 Ge2H6 (1)?
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