You will need the following data to do the calculations below. Parameter Eel Energy/cm-1 19735 VII 213.36 vx 0.14 v 122.31 vox E(I*) 0.883 7603 (a) Find the excited state dissociation energies, Do and Dé. In order to do this, you must find the convergence limit, max, which is the value where the excited state potential energy curve becomes asymptotic relative to the v" = 0 level. We can find this by taking the derivative of v with respect to order to solve for max. Referring to Figure 1, you can clearly see that + 1½), solving for (v' + 2)and substituting it back into equation (3) in max and Do = vmax - voo ve v'exé De = Dó + 2 4 (5) (6) (b) E(I*) is the energy difference between the dissociated I atoms from the ground state (I + I) and those from the excited state (I + I*) where I* indicates an I atom in the excited state (the result of energy being conserved upon dissociation). Using the data in Table 1 and the values that you calculated in part (a), calculate D" and Do" and the ground state zero-point energy. (c) Plot both the ground and excited state Morse potentials on the same graph. To do this, you will need the parameters that you calculated above along with the ground and excited state equilibrium internuclear separations, re" = 266.7 pm and ré= 297.1 pm, respectively. (d) Why is the excited state equilibrium internuclear separation, re, greater than it is for ground state, re"?
You will need the following data to do the calculations below. Parameter Eel Energy/cm-1 19735 VII 213.36 vx 0.14 v 122.31 vox E(I*) 0.883 7603 (a) Find the excited state dissociation energies, Do and Dé. In order to do this, you must find the convergence limit, max, which is the value where the excited state potential energy curve becomes asymptotic relative to the v" = 0 level. We can find this by taking the derivative of v with respect to order to solve for max. Referring to Figure 1, you can clearly see that + 1½), solving for (v' + 2)and substituting it back into equation (3) in max and Do = vmax - voo ve v'exé De = Dó + 2 4 (5) (6) (b) E(I*) is the energy difference between the dissociated I atoms from the ground state (I + I) and those from the excited state (I + I*) where I* indicates an I atom in the excited state (the result of energy being conserved upon dissociation). Using the data in Table 1 and the values that you calculated in part (a), calculate D" and Do" and the ground state zero-point energy. (c) Plot both the ground and excited state Morse potentials on the same graph. To do this, you will need the parameters that you calculated above along with the ground and excited state equilibrium internuclear separations, re" = 266.7 pm and ré= 297.1 pm, respectively. (d) Why is the excited state equilibrium internuclear separation, re, greater than it is for ground state, re"?
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter12: Thermodynamic Processes And Thermochemistry
Section: Chapter Questions
Problem 59P
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Transcribed Image Text:You will need the following data to do the calculations below.
Parameter
Eel
Energy/cm-1
19735
VII
213.36
vx
0.14
v
122.31
vox
E(I*)
0.883
7603
(a) Find the excited state dissociation energies, Do and Dé. In order to do this, you must find the
convergence limit, max, which is the value where the excited state potential energy curve
becomes asymptotic relative to the v" = 0 level. We can find this by taking the derivative of v
with respect to
order to solve for max. Referring to Figure 1, you can clearly see that
+ 1½), solving for (v' +
2)and substituting it back into equation (3) in
max
and
Do = vmax - voo
ve
v'exé
De = Dó +
2
4
(5)
(6)
(b) E(I*) is the energy difference between the dissociated I atoms from the ground state (I + I) and
those from the excited state (I + I*) where I* indicates an I atom in the excited state (the result
of energy being conserved upon dissociation). Using the data in Table 1 and the values that you
calculated in part (a), calculate D" and Do" and the ground state zero-point energy.
(c) Plot both the ground and excited state Morse potentials on the same graph. To do this, you will
need the parameters that you calculated above along with the ground and excited state
equilibrium internuclear separations, re" = 266.7 pm and ré= 297.1 pm, respectively.
(d) Why is the excited state equilibrium internuclear separation, re, greater than it is for ground
state, re"?
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