You will need a z table and ONE of the z score formulas for this question. Pretend there is pre-employment test with normally distributed scores and a mean =50 and standard deviation =10. What score would you have to get on the test to score in the top or highest 1%? A. 73.25 B. 75 C. 78 D. 50.25
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.
| A. | 73.25 | |
| B. | 75 | |
| C. | 78 | |
| D. | 50.25 |
X ~ N(50, 10)
The highest score to get on the test.
1% is equivalent to a z value of 0.50399.
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