You use 43.29 mL of Na2S₂O3 solution to titrate 0.1765 g of KIO3 (214.0 g/mole). KIO3 (aq) + 6HCl (aq) + 5 KI (aq) → 3 1₂ (aq) + 3 H₂O (1) + 6 KCl (aq) 2 Na₂S₂O3(aq) + 1₂ (aq) → Na₂S₂O6 (aq) + 2 Nal (aq) How many moles of KIO3 were used? (enter just the number in decimal form with correct sig. figs) mol KIO3. How many moles of Na2S₂O3 were present? (enter just the number in decimal form with correct sig. figs) mol Na₂S₂O3. What is the molar concentration of the Na2S₂O3 solution? (enter just the number in decimal form with correct sig. figs) M Na2S₂O3 solution

You use 43.29 mL of Na2S₂O3 solution to titrate 0.1765 g of KIO3 (214.0 g/mole). KIO3 (aq) + 6HCl (aq) + 5 KI (aq) → 3 1₂ (aq) + 3 H₂O (1) + 6 KCl (aq) 2 Na₂S₂O3(aq) + 1₂ (aq) → Na₂S₂O6 (aq) + 2 Nal (aq) How many moles of KIO3 were used? (enter just the number in decimal form with correct sig. figs) mol KIO3. How many moles of Na2S₂O3 were present? (enter just the number in decimal form with correct sig. figs) mol Na₂S₂O3. What is the molar concentration of the Na2S₂O3 solution? (enter just the number in decimal form with correct sig. figs) M Na2S₂O3 solution

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

You use 43.29 mL of Na₂S₂03 solution to titrate 0.1765 g of KIO3 (214.0 g/mole).
KIO3 (aq) + 6HCI (aq) + 5 KI (aq) → 3 1₂ (aq) + 3 H₂O (1) + 6 KCI (aq)
2 Na₂S₂03 (aq) +1₂ (aq) → Na₂S406 (aq) + 2 Nal (aq)
How many moles of KIO3 were used? (enter just the number in decimal form with correct sig. figs)
mol KIO3.
How many moles of Na2S₂03 were present? (enter just the number in decimal form
with correct sig. figs)
mol Na2S₂O3.
What is the molar concentration of the Na2S₂O3 solution? (enter just the number in
decimal form with correct sig. figs)
M Na2S₂O3 solution

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