Help Problem #22-D Motion Horizontally Launched Projectiles Part 1You are now visiting the Washington Monument in Washington, DC.You take a frisbee to the top of the WashingtonMonument and send it sailing along horizontallyat a speed of 5 m/s from the very top of thestructure, which is 169.2 m above the ground.A) How long will the frisbee remain in the air?(Remember--perfect physics world--no airresistance!)B) How far down range will the frisbee go(down range - horizontal distance.)?Sign out€

Name: Help Problem #22-D Motion Horizontally Launched Projectiles Part 1You
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Description: Help Problem #22-D Motion Horizontally Launched Projectiles Part 1You are now visiting the Washington Monument in Washington, DC.You take a frisbee to the top of the WashingtonMonument and send it sailing along horizontallyat a speed of 5 m/s from th

Answered: You take a frisbee to the top of the…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Problem #2
2-D Motion Horizontally Launched Projectiles Part 1
You are now visiting the Washington Monument in Washington, DC.
You take a frisbee to the top of the Washington
Monument and send it sailing along horizontally
at a speed of 5 m/s from the very top of the
structure, which is 169.2 m above the ground.
A) How long will the frisbee remain in the air?
(Remember--perfect physics world--no air
resistance!)
B) How far down range will the frisbee go
(down range - horizontal distance.)?
Sign out
€

Expert Solution

Step 1

Given that,

A frisbee sent horizontally from the top of the building

The initial speed of frisbee is $u = 5 (m / s)$

And the height of the building is $H = 169.2 (m)$

So the horizontal component of the initial speed of frisbee is $u_{x} = u = 5 (m / s)$

And the vertical component of the initial speed of frisbee is $u_{y} = 0 (m / s)$

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