Suppose that in a random selection of 100 colored candies, 19% of them are blue. The candy company claims hat the percentage of blue candies is equal to 31%. Use a 0.05 significance level to test that claim. pq n dentify the number of events, the number of trials, the claimed population proportion, and the significance evel to be used in technology. The number of events is 19, the number of trials is 100, the claimed population proportion is 0.31, and the significance level is 0.05. Jse technology to identify the test statistic for this hypothesis test, rounding to two decimal places. The test statistic for this hypothesis test is -2.59. n a hypothesis test, the P-value is the probability of getting a value of the test statistic that is at least as extreme as the test statistic obtained from the sample data, assuming that the null hypothesis is true. While he P-value can be found using technology or the standard normal distribution table, for this problem se technology, rounding to three decimal places. The P-value for this hypothesis test is 0.009. f P-value ≤ a, reject Ho. If P-value > x, fail to reject Ho. Then, use this information to state a final conclusion hat addresses the original claim with wording that can be understood by those without knowledge of statistical procedures.
Suppose that in a random selection of 100 colored candies, 19% of them are blue. The candy company claims hat the percentage of blue candies is equal to 31%. Use a 0.05 significance level to test that claim. pq n dentify the number of events, the number of trials, the claimed population proportion, and the significance evel to be used in technology. The number of events is 19, the number of trials is 100, the claimed population proportion is 0.31, and the significance level is 0.05. Jse technology to identify the test statistic for this hypothesis test, rounding to two decimal places. The test statistic for this hypothesis test is -2.59. n a hypothesis test, the P-value is the probability of getting a value of the test statistic that is at least as extreme as the test statistic obtained from the sample data, assuming that the null hypothesis is true. While he P-value can be found using technology or the standard normal distribution table, for this problem se technology, rounding to three decimal places. The P-value for this hypothesis test is 0.009. f P-value ≤ a, reject Ho. If P-value > x, fail to reject Ho. Then, use this information to state a final conclusion hat addresses the original claim with wording that can be understood by those without knowledge of statistical procedures.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Can you explain why the number of
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Suppose that in a random selection of 100 colored candies, 19% of them are blue. The candy company claims
that the percentage of blue candies is equal to 31%. Use a 0.05 significance level to test that claim.
pq
n
Identify the number of events, the number of trials, the claimed population proportion, and the significance
level to be used in technology.
The number of events is 19, the number of trials is 100, the claimed population proportion is 0.31, and the
significance level is 0.05.
X
Use technology to identify the test statistic for this hypothesis test, rounding to two decimal places.
The test statistic for this hypothesis test is - 2.59.
In a hypothesis test, the P-value is the probability of getting a value of the test statistic that is at least as
extreme as the test statistic obtained from the sample data, assuming that the null hypothesis is true. While
the P-value can be found using technology or the standard normal distribution table, for this problem
use technology, rounding to three decimal places.
The P-value for this hypothesis test is 0.009.
If P-value ≤ α, reject Ho. If P-value > a, fail to reject Hỏ. Then, use this information to state a final conclusion
that addresses the original claim with wording that can be understood by those without knowledge of statistical
procedures.
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Follow-up Question
You said the P-value is 0.995339, if that is the p-value, why arent we multiplying 0.995339 by 2 instead of 0.004661? Are you assuming that the p-value 0.995339 is for the left-tail and if so why?
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