You plotted a graph of current vs. voltage and found the slope of the best fit line is m± Am = 4.69 ±1.79 Amps/Volt. The resistance can be calculated from 1 the slope by knowing: R m The fractional uncertainty in the slope is equivalent to the fractional uncertainty in the resistance: AR Am R m = ᎪᎡ - Calculate the uncertainty in the resistance, AR in units of (ohms), then enter the raw value (no units) into the box below. Round to two decimal places. =
You plotted a graph of current vs. voltage and found the slope of the best fit line is m± Am = 4.69 ±1.79 Amps/Volt. The resistance can be calculated from 1 the slope by knowing: R m The fractional uncertainty in the slope is equivalent to the fractional uncertainty in the resistance: AR Am R m = ᎪᎡ - Calculate the uncertainty in the resistance, AR in units of (ohms), then enter the raw value (no units) into the box below. Round to two decimal places. =
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![You plotted a graph of current vs. voltage and found the slope of the best fit line is
\[ m \pm \Delta m = 4.69 \pm 1.79 \, \text{Amps/Volt}. \]
The resistance can be calculated from the slope by knowing:
\[ R = \frac{1}{m} \]
The fractional uncertainty in the slope is equivalent to the fractional uncertainty in the resistance:
\[ \frac{\Delta R}{R} = \frac{\Delta m}{m} \]
Calculate the uncertainty in the resistance, \( \Delta R \) in units of \( \Omega \) (ohms), then enter the raw value (no units) into the box below. **Round to two decimal places.**
\[ \Delta R = \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0ab47578-81e4-46a2-abcb-43bbb3318efe%2Fc160d167-407c-4e9e-b3f9-8c1266b0bfe9%2Fkzao6q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:You plotted a graph of current vs. voltage and found the slope of the best fit line is
\[ m \pm \Delta m = 4.69 \pm 1.79 \, \text{Amps/Volt}. \]
The resistance can be calculated from the slope by knowing:
\[ R = \frac{1}{m} \]
The fractional uncertainty in the slope is equivalent to the fractional uncertainty in the resistance:
\[ \frac{\Delta R}{R} = \frac{\Delta m}{m} \]
Calculate the uncertainty in the resistance, \( \Delta R \) in units of \( \Omega \) (ohms), then enter the raw value (no units) into the box below. **Round to two decimal places.**
\[ \Delta R = \]
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