You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 18.2 19.1 22.9 18.4 20.9 18.1 Find the 99% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place). 99% C.I. = Answer should be obtained without any preliminary rounding.
You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 18.2 19.1 22.9 18.4 20.9 18.1 Find the 99% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place). 99% C.I. = Answer should be obtained without any preliminary rounding.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![**Estimating the Mean Temperature and Finding the 99% Confidence Interval**
For this exercise, you need to estimate the mean temperature (in degrees Fahrenheit) using the provided sample temperatures:
- 18.2
- 19.1
- 22.9
- 18.4
- 20.9
- 18.1
### Procedure:
1. **Find the 99% Confidence Interval**:
Enter your answer as an open-interval (i.e., use parentheses) and ensure it’s accurate to two decimal places since the sample data is recorded to one decimal place.
Example format: (lower bound, upper bound)
2. Use the data provided to calculate the mean and standard deviation, and then apply the relevant statistical formula to determine the 99% confidence interval.
**Formula:**
\[ CI = \left( \overline{x} - Z_{\alpha/2} \left(\frac{\sigma}{\sqrt{n}}\right), \overline{x} + Z_{\alpha/2} \left(\frac{\sigma}{\sqrt{n}}\right) \right) \]
Where:
- \(\overline{x}\) = sample mean
- \(Z_{\alpha/2}\) = Z-score corresponding to the desired confidence level
- \(\sigma\) = sample standard deviation
- \(n\) = sample size
### 99% C.I. = ___
Answer should be obtained without any preliminary rounding.
**Graph Explanation:**
There are no graphs or diagrams included in this problem. The task solely involves textual analysis and mathematical calculations based on the given sample temperatures.
---
This transcription includes all the tasks and context from the original image, ensuring clarity on how to solve for the confidence interval with the given data.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd120f3b3-582e-4ce3-bf67-95261f57ecc8%2Feecf4187-6a2e-4e79-b72c-f04f3986acd6%2Fhz437g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Estimating the Mean Temperature and Finding the 99% Confidence Interval**
For this exercise, you need to estimate the mean temperature (in degrees Fahrenheit) using the provided sample temperatures:
- 18.2
- 19.1
- 22.9
- 18.4
- 20.9
- 18.1
### Procedure:
1. **Find the 99% Confidence Interval**:
Enter your answer as an open-interval (i.e., use parentheses) and ensure it’s accurate to two decimal places since the sample data is recorded to one decimal place.
Example format: (lower bound, upper bound)
2. Use the data provided to calculate the mean and standard deviation, and then apply the relevant statistical formula to determine the 99% confidence interval.
**Formula:**
\[ CI = \left( \overline{x} - Z_{\alpha/2} \left(\frac{\sigma}{\sqrt{n}}\right), \overline{x} + Z_{\alpha/2} \left(\frac{\sigma}{\sqrt{n}}\right) \right) \]
Where:
- \(\overline{x}\) = sample mean
- \(Z_{\alpha/2}\) = Z-score corresponding to the desired confidence level
- \(\sigma\) = sample standard deviation
- \(n\) = sample size
### 99% C.I. = ___
Answer should be obtained without any preliminary rounding.
**Graph Explanation:**
There are no graphs or diagrams included in this problem. The task solely involves textual analysis and mathematical calculations based on the given sample temperatures.
---
This transcription includes all the tasks and context from the original image, ensuring clarity on how to solve for the confidence interval with the given data.
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