You measure 30 watermelons' weights, and find they have a mean weight of 43 ounces. Assume the population standard deviation is 3 ounces. Based on this, construct a 95% confidence interval for the true population mean watermelon weight. Give your answers as decimals, to two places ounces

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**Constructing a 95% Confidence Interval for Watermelon Weights**

In this exercise, you have measured the weights of 30 watermelons and found that they have a mean weight of 43 ounces. Given that the population standard deviation is 3 ounces, your task is to construct a 95% confidence interval for the true population mean watermelon weight.

### Steps to Construct the Confidence Interval

1. **Identify the Sample Mean and Standard Deviation:**
   - Sample mean (\(\bar{x}\)): 43 ounces
   - Population standard deviation (\(\sigma\)): 3 ounces
  
2. **Sample Size:** \(n = 30\)

3. **Determine the Z-Score for a 95% Confidence Level:**
   - For a 95% confidence level, the Z-score is approximately 1.96 (based on standard normal distribution).

4. **Calculate the Standard Error (SE):**
   \[
   SE = \frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{30}}
   \]

5. **Calculate the Margin of Error (ME):**
   \[
   ME = Z \times SE = 1.96 \times \frac{3}{\sqrt{30}}
   \]

6. **Construct the Confidence Interval:**
   - Lower limit: \(\bar{x} - ME\)
   - Upper limit: \(\bar{x} + ME\)

By filling in the required values and performing the calculations, you will obtain the confidence interval expressed as decimals to two places.

### Enter Your Results

Please enter your calculated lower and upper limits in the designated response fields in ounces.

---

**Note:** If you need assistance with any part of this exercise, feel free to message your instructor for guidance.

**Submit your answers** using the 'Submit Question' button once you have completed the calculations.
Transcribed Image Text:**Constructing a 95% Confidence Interval for Watermelon Weights** In this exercise, you have measured the weights of 30 watermelons and found that they have a mean weight of 43 ounces. Given that the population standard deviation is 3 ounces, your task is to construct a 95% confidence interval for the true population mean watermelon weight. ### Steps to Construct the Confidence Interval 1. **Identify the Sample Mean and Standard Deviation:** - Sample mean (\(\bar{x}\)): 43 ounces - Population standard deviation (\(\sigma\)): 3 ounces 2. **Sample Size:** \(n = 30\) 3. **Determine the Z-Score for a 95% Confidence Level:** - For a 95% confidence level, the Z-score is approximately 1.96 (based on standard normal distribution). 4. **Calculate the Standard Error (SE):** \[ SE = \frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{30}} \] 5. **Calculate the Margin of Error (ME):** \[ ME = Z \times SE = 1.96 \times \frac{3}{\sqrt{30}} \] 6. **Construct the Confidence Interval:** - Lower limit: \(\bar{x} - ME\) - Upper limit: \(\bar{x} + ME\) By filling in the required values and performing the calculations, you will obtain the confidence interval expressed as decimals to two places. ### Enter Your Results Please enter your calculated lower and upper limits in the designated response fields in ounces. --- **Note:** If you need assistance with any part of this exercise, feel free to message your instructor for guidance. **Submit your answers** using the 'Submit Question' button once you have completed the calculations.
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