You measure 49 watermelons' weights, and find they have a mean weight of 41 ounces. Assume the population standard deviation is 4 ounces. Based on this, construct a 99% confidence interval for the true population mean watermelon weight. Give your answers as decimals, to two places ounces
You measure 49 watermelons' weights, and find they have a mean weight of 41 ounces. Assume the population standard deviation is 4 ounces. Based on this, construct a 99% confidence interval for the true population mean watermelon weight. Give your answers as decimals, to two places ounces
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![You measure 49 watermelons' weights, and find they have a mean weight of 41
ounces. Assume the population standard deviation is 4 ounces. Based on this,
construct a 99% confidence interval for the true population mean watermelon weight.
Give your answers as decimals, to two places
ounces](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0fefe08f-70f1-4e7f-aca9-fa95af3c079c%2Fef785e8c-b2b2-4488-ae76-4c385c95ae5b%2Fz9o59d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:You measure 49 watermelons' weights, and find they have a mean weight of 41
ounces. Assume the population standard deviation is 4 ounces. Based on this,
construct a 99% confidence interval for the true population mean watermelon weight.
Give your answers as decimals, to two places
ounces
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
The 99% confidence interval for the true population mean watermelon weight is obtained below:
The value of mean weight is 41 ounces, population standard deviation is 4 ounces and sample size (n) = 49
Critical value:
From the standard normal distribution table, for the 99% confidence level the critical values is (z*) 2.58.
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