You measure 23 watermelons' weights, and find they have a mean weight of 39 ounces. Assume the population standard deviation is 7.4 ounces. Based on this, construct a 90% confidence interval for the true population mean watermelon weight. Do not use StatCrunch. Show all formulas used, work, etc. Be sure to define your variables. As in the reading, in your calculations: --Use z = 1.645 for a 90% confidence interval --Use z = 1.96 for a 95% confidence interval --Use z = 2.576 for a 99% confidence interval Give your answer as an inequality rounded to one decimal place. Then interpret your answer in a complete sentence within the context of the problem.
You measure 23 watermelons' weights, and find they have a
Do not use StatCrunch. Show all formulas used, work, etc. Be sure to define your variables. As in the reading, in your calculations:
--Use z = 1.645 for a 90% confidence interval
--Use z = 1.96 for a 95% confidence interval
--Use z = 2.576 for a 99% confidence interval
Give your answer as an inequality rounded to one decimal place. Then interpret your answer in a complete sentence within the context of the problem.
Given
The data is as follows:
Sample size,
Sample mean,
Population sd,
CL=0.90
z-critical value = 1.645
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