You may want to reference (Pages 80 - 87) Sections 3.6-3.7 while completing this problem. A 143-g sample of steam at 100 °C is emitted from a volcano. It condenses, cools, and falls as snow at 0 °C. (For water, 80. cal (334 J) is needed to melt 1 g of ice or must be removed to freeze 1 g of water and 540 cal (2260 J) is needed to convert 1 g of water to vapor at 100 °C.) Part A How many kilojoules of heat were released? Express your answer with the appropriate units. HẢ Heat = 370.6 kJ Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining
You may want to reference (Pages 80 - 87) Sections 3.6-3.7 while completing this problem. A 143-g sample of steam at 100 °C is emitted from a volcano. It condenses, cools, and falls as snow at 0 °C. (For water, 80. cal (334 J) is needed to melt 1 g of ice or must be removed to freeze 1 g of water and 540 cal (2260 J) is needed to convert 1 g of water to vapor at 100 °C.) Part A How many kilojoules of heat were released? Express your answer with the appropriate units. HẢ Heat = 370.6 kJ Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining
Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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You may want to reference (Pages 80 - 87) Sections 3.6-3.7 while completing this problem.
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A 143-g sample of steam at 100 °C is emitted from a volcano. It condenses, cools, and falls as snow at 0°C. (For water, 80. cal (334 J) is needed to melt 1 g of ice or must be removed
to freeze 1 g of water and 540 cal (2260 J) is needed to convert 1 g of water to vapor at 100 °C.)
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Part A
How many kilojoules of heat were released?
Express your answer with the appropriate units.
?
Heat = 370.6
kJ
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Previous Answers Request Answer
X Incorrect; Try Again; 2 attempts remaining
Be sure to also include the heat released during the cooling of water from 100 °C to 0°C in your calculations.
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Expert Solution

Step 1
Given information,
Mass of sample (m) = 143 g
Initial temperature (T1) = 100°C
Final temperature (T2) = 0°C
Change in temperature (∆T) = T2 - T1 = 0°C - 100°C = -100°C
∆Hfus = 334 J/g
∆Hvap = 2260 J/g
Additional information,
Specific heat capacity of liquid water (c) = 4.18 J/g °C
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