An eager scientist on a hot summer day needs to determine how much ice to buy. She has a cooler which is filled with 36 cans of soda at a temperature of 86.5°F. Each can has a mass of 384 g. The scientist wants the temperature of the drinks to be 40.8°F. If there is no heat lost by the cooler and ignoring any heat lost to the soda containers, what mass mjce of ice needs must she add to her cooler? Assume the temperature of the ice is 32.0 °F. The latent heat of fusion for ice is 80.0 cal/g, the specific heat of water is 1.00 cal/g.°C, the specific heat of the soda is 0.900 cal/g.°C, and there are 454 grams per pound. Mice = lbs

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Problem:**

An eager scientist on a hot summer day needs to determine how much ice to buy. She has a cooler which is filled with 36 cans of soda at a temperature of 86.5°F. Each can has a mass of 384 g. The scientist wants the temperature of the drinks to be 40.8°F.

If there is no heat lost by the cooler and ignoring any heat lost to the soda containers, what mass \(m_{\text{ice}}\) of ice must she add to her cooler? Assume the temperature of the ice is 32.0°F. The latent heat of fusion for ice is 80.0 cal/g, the specific heat of water is 1.00 cal/g·°C, the specific heat of the soda is 0.900 cal/g·°C, and there are 454 grams per pound.

\[ m_{\text{ice}} = \text{__________ lbs} \]
Transcribed Image Text:**Problem:** An eager scientist on a hot summer day needs to determine how much ice to buy. She has a cooler which is filled with 36 cans of soda at a temperature of 86.5°F. Each can has a mass of 384 g. The scientist wants the temperature of the drinks to be 40.8°F. If there is no heat lost by the cooler and ignoring any heat lost to the soda containers, what mass \(m_{\text{ice}}\) of ice must she add to her cooler? Assume the temperature of the ice is 32.0°F. The latent heat of fusion for ice is 80.0 cal/g, the specific heat of water is 1.00 cal/g·°C, the specific heat of the soda is 0.900 cal/g·°C, and there are 454 grams per pound. \[ m_{\text{ice}} = \text{__________ lbs} \]
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