You may need to use the appropriate appendix table or technology to answer this question. Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production process. Assume a production process produces items with a mean weight of 10 ounces. (a) The process standard deviation is 0.16, and the process control is set at plus or minus one standard deviation. Units with weights less than 9.84 or greater than 10.16 ounces will be classified as defects. (Round your answer to the nearest integer.) Calculate the probability of a defect. (Round your answer to four decimal places.) Calculate the expected number of defects for a 1,000-unit production run. (Round your answer to the nearest integer.) defects (b) Through process design improvements, the process standard deviation can be reduced to 0.08. Assume the process control remains the same, with weights less than 9.84 or greater than 10.16 ounces being classified as defects. Calculate the probability of a defect. (Round your answer to four decimal places.) Calculate the expected number of defects for a 1,000-unit production run. (Round your answer to the nearest integer.) defects (c) What is the advantage of reducing process variation, thereby causing process control limits to be at a greater number of standard deviations from the mean? a. Reducing the process standard deviation causes a substantial reduction in the number of defects. b. Reducing the process standard deviation causes no change in the number of defects. c. Reducing the process standard deviation causes a substantial increase in the number of defects.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.4: Distributions Of Data

Problem 19PFA

See similar textbooks

Related questions

Question

You may need to use the appropriate appendix table or technology to answer this question. Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production process. Assume a production process produces items with a mean weight of 10 ounces. (a) The process standard deviation is 0.16, and the process control is set at plus or minus one standard deviation. Units with weights less than 9.84 or greater than 10.16 ounces will be classified as defects. (Round your answer to the nearest integer.) Calculate the probability of a defect. (Round your answer to four decimal places.) Calculate the expected number of defects for a 1,000-unit production run. (Round your answer to the nearest integer.) defects (b) Through process design improvements, the process standard deviation can be reduced to 0.08. Assume the process control remains the same, with weights less than 9.84 or greater than 10.16 ounces being classified as defects. Calculate the probability of a defect. (Round your answer to four decimal places.) Calculate the expected number of defects for a 1,000-unit production run. (Round your answer to the nearest integer.) defects (c) What is the advantage of reducing process variation, thereby causing process control limits to be at a greater number of standard deviations from the mean? a. Reducing the process standard deviation causes a substantial reduction in the number of defects. b. Reducing the process standard deviation causes no change in the number of defects. c. Reducing the process standard deviation causes a substantial increase in the number of defects.

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Expert Solution