**Question 5:** You may need to use the appropriate appendix table or technology to answer this question.A sample of 225 elements from a population with a standard deviation of 90 is selected. The sample mean is 175. Find the 98% confidence interval for μ.- ○ 170 to 180- ○ 85 to 265- ○ 162.7 to 187.3- ○ 161.042 to 188.958**Notes for Students:**To calculate the 98% confidence interval for the population mean (μ), you will use the formula for the confidence interval:\[ \text{Confidence Interval} = \bar{x} \pm z \left(\frac{\sigma}{\sqrt{n}}\right) \]Where:- \( \bar{x} \) is the sample mean- \( z \) is the z-score corresponding to the desired confidence level- \( \sigma \) is the population standard deviation- \( n \) is the sample sizeUse the provided details and choose the correct confidence interval from the options.

Since we know population standard deviation, use z-distribution to find z-critical value. Find…

You may need to use the appropriate appendix table or technology to answer this question. A sample of 225 elements from a population with a standard deviation of 90 is selected. The sample mean is 175. Find the 98% confidence interval for u. O 170 to 180 O 85 to 265 O 162.7 to 187.3 O 161.042 to 188.958

You may need to use the appropriate appendix table or technology to answer this question. A sample of 225 elements from a population with a standard deviation of 90 is selected. The sample mean is 175. Find the 98% confidence interval for u. O 170 to 180 O 85 to 265 O 162.7 to 187.3 O 161.042 to 188.958

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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