You intend to estimate a population mean \( \mu \) with the following sample.| | ||---|---|| **35.1** || **68.7** || **46.7** || **42.7** || **37** || **7.9** || **41.5** || **47** || **24.1** || **30.5** |You believe the population is normally distributed. Find the 99.9% confidence interval. Enter your answer as an **open-interval** (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place).99.9% C.I. = \( \underline{ \ \ \ \ \ \ \ \ \ \ } \)Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.

Obtain the 99.9% confidence interval for the population mean. The 99.9% confidence interval for the…

Answered: You intend to estimate a population…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Read and answer the following questions. Write your answers on a sheet of paper. 1. The mean and standard deviation of n measurements randomly sampled from a normally distributed population are 33 and 4, respectively. Construct a 95% confidence interval for the population mean for each given n. b. n-15 C. n 20 a. were
A statistics instructor randomly selected four bags of oranges, each bag labeled 10 pounds, and weighed the bags. They weighed 10.3, 10.8, 10.4, and 10.6 pounds. Assume that the distribution of weights is Normal. Find a 95% confidence interval for the mean weight of all bags of oranges. Use technology for your calculations. Answer parts a and b below. a. Choose the correct interpretation of the confidence interval below and, if necessary, fill in the answer boxes to complete your choice. A. We are 95% confident the population mean is between and B. There is a 95% chance that all intervals will be between and C. We are 95% confident that the sample mean is between and D. The requirements for constructing a confidence interval are not satisfied. (Type integers or decimals rounded to the nearest thousandth as needed. Use ascending order.)
According to IT department of leading financial firm, 50% of emails received by their employees are spam. They are planning to install a software which filters the spam emails. A reputable cybersecurity brand has launched a software which claims to detect 99% of spam emails. However, they have also reported 5% as the chance of detecting a non-spam email as spam. If an email is detected as spam, what is the probability of it in fact being a non-spam email?
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intending to estimate a population mean μ with the following sample. 32 39.3 38.9 39.6 3.6 55.1 30.6 41.5 -1 believing the population is normally distributed. Find the 99.5% confidence interval. Enter answer as an open-interval to two decimal places 99.5% C.I. =
You intend to estimate a population mean u with the following sample. 95.6 77.1 72.5 83.2 81.1 72.3 73.4 63.1 You believe the population is normally distributed. Find the 99.5% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places (because the sample data are reported accurate to one decimal place). 99.5% C.I. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places. Submit Question Ce Ol 96 & 3. 00 27 %23
You intend to estimate a population mean u with the following sample. 3.3 41.8 3.4 39.9 47.8 68.7 32 -0.9 29.1 You believe the population is normally distributed. Find the 99.9% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places (because the sample data are reported accurate to one decimal place). 99.9% C.I. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
You intend to estimate a population mean u with the following sample. 31.6 30 6.9 26.2 17.9 31.3 26.6 26.8 You believe the population is normally distributed. Find the 99.5% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places (because the sample data are reported accurate to one decimal place). 99.5% C.I. =
Find the 99% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place).99% C.I. =
You intend to estimate a population mean μ with the following sample. 72.5 63.8 60.9 74.5 64.2 62.3 66.5 80.7 77.1 85.2 84 You believe the population is normally distributed. Find the 99.5% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places (because the sample data are reported accurate to one decimal place).99.5% C.I. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
10 The interval estimate is, a 12.2 13.4 b 11.8 13.8 c 11.1 14.5 d 10.0 15.6
his question refers to excavations at a national monument. One question the archaeologists asked was: Is raw material used by prehistoric Indians for stone tool manufacture independent of the archaeological excavation site? Two different excavation sites gave the information in the following table. Use a chi-square test with 5% level of significance to test the claim that raw material used for construction of stone tools and excavation site are independent. Excavation Site Material Site A Site B Row Total Basalt 756 559 1315 Obsidian 92 103 195 Pedernal chert 514 521 1035 Other 88 91 179 Column Total 1450 1274 2724 (a) What is the level of significance? (b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least three decimal places. Round the test statistic to three decimal places.)

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