**Estimating a Population Mean with a Sample**You intend to estimate a population mean $ \mu $ using the following sample:\[\begin{array}{c}-7 \\1.3 \\10.2 \\28.8 \\33.7 \\21.3 \\6.6 \\-3.4 \\\end{array}\]### TaskYou believe the population is normally distributed. Your goal is to find the 99% confidence interval. - **Instructions:** Enter your answer as an open interval (i.e., in parentheses) accurate to two decimal places, based on the sample data reported to one decimal place.- **99% Confidence Interval:** $ 99\% \text{ C.I.} = $ [Input Box]**Note:** The answer should be obtained without any preliminary rounding. However, the critical value can be rounded to three decimal places. ### Selections- Radio Button: [ ] Yes- Radio Button: [ ] No

Solution-: We find 99% C.I. for the

Answered: You intend to estimate a population…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A random sample of 35 customers has an average order size of $80, and a population standard deviation of $22.00. Not all samples of this size would give you the same sample average, so you'd like to construct an "interval estimate" to convey this uncertainty. What is a 95% confidence interval for this mean? Group of answer choices a $78.77 - $81.23 b $72.56 - $87.44 c $36.88 - $123.12 d $72.71 - $87.29
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
AA A www-awn.aleks.com t1 items wai... T (1) THE STYLE... ** lissa Black Lo... Bb Thread: Week... X A ALEKS - Shasi... O CONFIDENCE INTERVALS AND HYPOTHESIS TESTL. Confidence interval for the population. Shasia v OOD OC The following data were randomly drawn from an approximately normal population. 17, 20, 25, 29, 33, 41, 44 (Send data to calculator (Send data to Excel Based on these data, find a 95% confidence interval for the population standard deviation. Then give its lower limit and upper limit. Carry your intermediate computations to at least three decimal places. Round your answers to at least two decimal places. (If necessary, consult a list of formulas.) Lower limit: I ? Upper limit: O Explanation Ch. +
You are interested in finding a 95% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 13 randomly selected college students. Round answers to 3 decimal places where possible. 7 5 3 9 11 6 4 12 0 6 0 6 2 With 95% confidence the population mean number of days of class that college students miss is between ------- and ----------- days.
You intend to estimate a population mean u with the following sample. 95.6 77.1 72.5 83.2 81.1 72.3 73.4 63.1 You believe the population is normally distributed. Find the 99.5% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places (because the sample data are reported accurate to one decimal place). 99.5% C.I. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places. Submit Question Ce Ol 96 & 3. 00 27 %23
You are interested in finding a 99% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 15 randomly selected college students. Round answers to 3 decimal places where possible. 1 7 12 10 2 0 9 0 7 11 6 11 10 2 12 b. With 99% confidence the population mean number of days of class that college students miss is between ? and ? days. c. If many groups of 15 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About ? percent of these confidence intervals will contain the true population mean number of missed class days and about ? percent will not contain the true population mean number of missed class days.
You intend to estimate a population mean u with the following sample. 3.3 41.8 3.4 39.9 47.8 68.7 32 -0.9 29.1 You believe the population is normally distributed. Find the 99.9% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places (because the sample data are reported accurate to one decimal place). 99.9% C.I. = Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
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You intend to estimate a population mean u with the following sample. 31.6 30 6.9 26.2 17.9 31.3 26.6 26.8 You believe the population is normally distributed. Find the 99.5% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places (because the sample data are reported accurate to one decimal place). 99.5% C.I. =
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96
You are interested in finding a 95% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 11 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 7 8 19 14 10 5 15 20 5 27 26 a. To compute the confidence interval use a ? v distribution. b. With 95% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 11 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per patient and about percent will not contain the true population mean number of visits per patient.
Find the 99% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place).99% C.I. =

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