E El- -|· El-welcome, CHASE BAIXLSearch topics and skillsLearningEAwardsA MathP RecommendationsYou have prizes to reveall Go to your ogLevel L * K.7 Proving trtangles congruent by SSS, SAS, ASA, and AAS SZLZVYW ZTXZ, WX YZ, and ZZ ZW, Complete the proof that AVWY E ATZX.WY.StatementReason1.ZVYW ZTXZGiven2WX E YZGlvenZZ ZWGlven4XZ = YZ + XYAII Tyne dInyies dre Longr ueLAngles forming a linear pair sum to 1800Definibion of angle bisectorDefinition of equilateral triangleDefinitionVertical Angle TheoremWY = WX + XYXZ = WX + XYWY = XZmidpoint8.AVWY E ATZXASASubmit

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You heve prizes to reveall Go to Level L * K.7 Proving trtangles congruent by SS5, SAS, ASA, and AAS sZL ZVYW E ZTXZ, WX = YZ, and ZZ = ZW. Complete the proof that AVWY ATZX. Statement Reason ZVYW W ZTXZ Glven 2. WX YZ Glven 3. ZZ ZW Glven 4 XZ = YZ + XY KII Tignt dingies dre Conyruent Angles forming a linear palr sum to 180° Definibion of angle bisector Definition of equilateral triangle Definition of mldpoint Vertical Angle Theorem ASA 5. WY = WX + XY 6. XZ = WX + XY WY = XZ 8. AVWY ATZX 1.

You heve prizes to reveall Go to Level L * K.7 Proving trtangles congruent by SS5, SAS, ASA, and AAS sZL ZVYW E ZTXZ, WX = YZ, and ZZ = ZW. Complete the proof that AVWY ATZX. Statement Reason ZVYW W ZTXZ Glven 2. WX YZ Glven 3. ZZ ZW Glven 4 XZ = YZ + XY KII Tignt dingies dre Conyruent Angles forming a linear palr sum to 180° Definibion of angle bisector Definition of equilateral triangle Definition of mldpoint Vertical Angle Theorem ASA 5. WY = WX + XY 6. XZ = WX + XY WY = XZ 8. AVWY ATZX 1.

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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the answer choices in box 2 and 10 may be wrong I need major assistance!
3. Use C.P. or I.P. or both to construct proofs for the following (= Unit 9 -plus the rules from Units 7 and 8) [0.75 mark each]. a. A (BVC), C = (E. F), ~ (F v B) /.. ~ A b. A (XY), B = (Dv~F), ~(Dv W), F = ~Y. (A. B) > ~ X c. A 7. T (E (BVC)), S = ~(Dv C), T (S. ~ B), ~ Av C (DVE) 1 [Extra credit, 1 mark] d. (C. (F v E)) v (C. ~ (F v E)), F~B, (AC) = ~ (X > E) /.. B > C