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You have seen how Kirchhoff's laws were used in your lectures to obtain a 2nd order differential equation where we solved for the current. This time we will use an even simpler concept: principle of conservation of energy to derive the 2nd order differential equation where we will solve for the charge. Take a look at the circuit below. :2F In the circuit above, we have a capacitor with capacitance 2 F, an inductor of inductance 5 H and a resistor of 32 (b) Now you know that the power dissipation through a resistor is -rR. Use the conservation of energy (energy gain rate = energy loss rate) to derive the differential equation in terms Q and t only. ele

You have seen how Kirchhoff's laws were used in your lectures to obtain a 2nd order differential equation where we solved for the current. This time we will use an even simpler concept: principle of conservation of energy to derive the 2nd order differential equation where we will solve for the charge. Take a look at the circuit below. :2F In the circuit above, we have a capacitor with capacitance 2 F, an inductor of inductance 5 H and a resistor of 32 (b) Now you know that the power dissipation through a resistor is -rR. Use the conservation of energy (energy gain rate = energy loss rate) to derive the differential equation in terms Q and t only. ele

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3. You have seen how Kirchhoff's laws were used in your lectures to obtain a 2nd order differential equation where we solved for the current. This time we will use an even simpler concept: principle of conservation of energy to derive the 2nd order differential equation where we will solve for the charge. Take a look at the circuit below. SHE =2F In the circuit above, we have a capacitor with capacitance 2 F, an inductor of inductance 5 H and a resistor of 3N (b) Now you know that the power dissipation through a resistor is -1*R. Use the conservation of energy (energy gain rate = energy loss rate) to derive the differential equation in terms Q andt only.
Transcribed Image Text:3. You have seen how Kirchhoff's laws were used in your lectures to obtain a 2nd order differential equation where we solved for the current. This time we will use an even simpler concept: principle of conservation of energy to derive the 2nd order differential equation where we will solve for the charge. Take a look at the circuit below. SHE =2F In the circuit above, we have a capacitor with capacitance 2 F, an inductor of inductance 5 H and a resistor of 3N (b) Now you know that the power dissipation through a resistor is -1*R. Use the conservation of energy (energy gain rate = energy loss rate) to derive the differential equation in terms Q andt only.
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