You have seen how Kirchhoff's laws were used in your lectures to obtain a 2nd order differential equation where we solved for the current. This time we will use an even simpler concept: principle of conservation of energy to derive the 2nd order differential equation where we will solve for the charge. Take a look at the circuit below. IHE +2F In the circuit above, we have a capacitor with capacitance 2 F , an inductor of inductance 5 H and a resistor of 32 (c) Solve the differential equation for initial charge to be Qo with a initial current of -0.3Q,/s.

icon
Related questions
Question
3. You have seen how Kirchhoff's laws were used in your lectures to obtain a 2nd
order differential equation where we solved for the current. This time we will
use an even simpler concept: principle of conservation of energy to derive the
2nd order differential equation where we will solve for the charge. Take a look
at the circuit below.
IHE
=2F
In the circuit above, we have a capacitor with capacitance 2 F, an inductor of
inductance 5 H and a resistor of 3N
(c) Solve the differential equation for initial charge to be Qo with a initial
current of –0.3Qo/s.
Transcribed Image Text:3. You have seen how Kirchhoff's laws were used in your lectures to obtain a 2nd order differential equation where we solved for the current. This time we will use an even simpler concept: principle of conservation of energy to derive the 2nd order differential equation where we will solve for the charge. Take a look at the circuit below. IHE =2F In the circuit above, we have a capacitor with capacitance 2 F, an inductor of inductance 5 H and a resistor of 3N (c) Solve the differential equation for initial charge to be Qo with a initial current of –0.3Qo/s.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 3 images

Blurred answer