You have an Attwood device where one block is on a smooth (frictionless), level table, attached to a block on a similarly smooth incline. Find the tension in the string and the acceleration of the blocks. m1=5 kg, m2=14 kg, and e=32°. Given ma= 5Ka O=3 29
You have an Attwood device where one block is on a smooth (frictionless), level table, attached to a block on a similarly smooth incline. Find the tension in the string and the acceleration of the blocks. m1=5 kg, m2=14 kg, and e=32°. Given ma= 5Ka O=3 29
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![### Physics: Mechanics - Atwood's Machine with an Incline
**Problem Description:**
You have an Atwood device where one block is on a smooth (frictionless) level table attached to a block on a similarly smooth incline. Find the tension in the string and the acceleration of the blocks. The given values are:
- Mass of block \( m_1 \) = 5 kg
- Mass of block \( m_2 \) = 14 kg
- Angle of incline \( \theta \) = 32°
**Diagram Explanation:**
The provided diagram illustrates an Atwood machine setup:
- A pulley system with two blocks connected by a string.
- Block \( m_1 \) (5 kg) is situated on a frictionless horizontal table.
- Block \( m_2 \) (14 kg) is situated on a frictionless incline.
- The angle \( \theta \) of the incline is 32°.
**Steps to Solve the Problem:**
1. **Free Body Diagram Analysis:**
- Draw the forces acting on each block.
- For block \( m_1 \): Tension \( T \) in the string acts horizontally.
- For block \( m_2 \): Gravity decomposes into two components - one parallel to the incline (\( m_2 g \sin\theta \)) and one perpendicular to the incline (\( m_2 g \cos\theta \)). Tension \( T \) acts upward along the incline.
2. **Equations of Motion:**
- Block \( m_1 \) (horizontal):
\[
T = m_1 a
\]
- Block \( m_2 \) (inclined):
\[
m_2 g \sin\theta - T = m_2 a
\]
3. **Solve for Tension (T) and Acceleration (a):**
By combining the equations:
\[
T = m_1 a \quad \text{(1)}
\]
\[
m_2 g \sin(\theta) - T = m_2 a \quad \text{(2)}
\]
Substitute \( T \) from equation (1) into equation (2):
\[
m_2 g \sin(\theta) - m_1 a = m_2 a
\]
Combine to solve for \( a \):
\[
m_](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F96058389-9737-4e92-9810-6187695664e8%2Fdebb71c2-d9b9-4a95-bcf2-96c4f2f70a98%2Fkebc63p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Physics: Mechanics - Atwood's Machine with an Incline
**Problem Description:**
You have an Atwood device where one block is on a smooth (frictionless) level table attached to a block on a similarly smooth incline. Find the tension in the string and the acceleration of the blocks. The given values are:
- Mass of block \( m_1 \) = 5 kg
- Mass of block \( m_2 \) = 14 kg
- Angle of incline \( \theta \) = 32°
**Diagram Explanation:**
The provided diagram illustrates an Atwood machine setup:
- A pulley system with two blocks connected by a string.
- Block \( m_1 \) (5 kg) is situated on a frictionless horizontal table.
- Block \( m_2 \) (14 kg) is situated on a frictionless incline.
- The angle \( \theta \) of the incline is 32°.
**Steps to Solve the Problem:**
1. **Free Body Diagram Analysis:**
- Draw the forces acting on each block.
- For block \( m_1 \): Tension \( T \) in the string acts horizontally.
- For block \( m_2 \): Gravity decomposes into two components - one parallel to the incline (\( m_2 g \sin\theta \)) and one perpendicular to the incline (\( m_2 g \cos\theta \)). Tension \( T \) acts upward along the incline.
2. **Equations of Motion:**
- Block \( m_1 \) (horizontal):
\[
T = m_1 a
\]
- Block \( m_2 \) (inclined):
\[
m_2 g \sin\theta - T = m_2 a
\]
3. **Solve for Tension (T) and Acceleration (a):**
By combining the equations:
\[
T = m_1 a \quad \text{(1)}
\]
\[
m_2 g \sin(\theta) - T = m_2 a \quad \text{(2)}
\]
Substitute \( T \) from equation (1) into equation (2):
\[
m_2 g \sin(\theta) - m_1 a = m_2 a
\]
Combine to solve for \( a \):
\[
m_
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