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You have a 2.5 GHz workstation with 6 cores where each core can do 6 floating point operations per clock cycle. Consider the n by n linear system Ax = b where A is tridiagonal. Estimate the largest value of n such that the linear system can be solved in 140 minutes. O 2.75E7 1.04E5 O 1.31E5 9.45E13

You have a 2.5 GHz workstation with 6 cores where each core can do 6 floating point operations per clock cycle. Consider the n by n linear system Ax = b where A is tridiagonal. Estimate the largest value of n such that the linear system can be solved in 140 minutes. O 2.75E7 1.04E5 O 1.31E5 9.45E13

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The computational complexities of some common operations with n by n matrices are given in the table below. Operations Matrix-matrix multiplication Flops 2n3 Matrix-vector multiplication 2n2 2n /3 + O(n²) n3 /3 + O(n²) LU factorization Cholesky factorization Back/forward substitution n2 Tridiagonal solve 8n You have a 2.5 GHz workstation with 6 cores where each core can do 6 floating point operations per clock cycle. Consider the n by n linear system Ax 140 minutes. b where A is tridiagonal. Estimate the largest value of n such that the linear system can be solved in || 2.75E7 1.04E5 1.31E5 9.45E13
Transcribed Image Text:The computational complexities of some common operations with n by n matrices are given in the table below. Operations Matrix-matrix multiplication Flops 2n3 Matrix-vector multiplication 2n2 2n /3 + O(n²) n3 /3 + O(n²) LU factorization Cholesky factorization Back/forward substitution n2 Tridiagonal solve 8n You have a 2.5 GHz workstation with 6 cores where each core can do 6 floating point operations per clock cycle. Consider the n by n linear system Ax 140 minutes. b where A is tridiagonal. Estimate the largest value of n such that the linear system can be solved in || 2.75E7 1.04E5 1.31E5 9.45E13
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