You hang a 30 kg mass from the end of a rod that is 12 m by 2 mm by 2 mm. You observe that the rod's length increases to 12.3 m. (Take g=9.8 m/s²) 1) 2) The tension in the rod FT = 3) the rod is A = The strain in the rod is The cross-sectional area of

College Physics
11th Edition
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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You hang a 30 kg mass from
the end of a rod that is 12 m by 2 mm by 2
mm. You observe that the rod's length
increases to 12.3 m. (Take g-9.8 m/s²)
1)
2)
The tension in the rod FT =
3)
the rod is A =
The strain in the rod is
The cross-sectional area of
◄►
Important remark:
In Moodle, the number 2 x 10-³ is written
as 2e-3 or 2*10^-3. Don't use the letter x for
multiplication.
Transcribed Image Text:You hang a 30 kg mass from the end of a rod that is 12 m by 2 mm by 2 mm. You observe that the rod's length increases to 12.3 m. (Take g-9.8 m/s²) 1) 2) The tension in the rod FT = 3) the rod is A = The strain in the rod is The cross-sectional area of ◄► Important remark: In Moodle, the number 2 x 10-³ is written as 2e-3 or 2*10^-3. Don't use the letter x for multiplication.
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