You found that the reduction formula of a certain integral is In = 180 (13x" sin (13x) + næ"-1 cos (13x) – n (n – 1) In-2] 169 1 and that I =R a sin (13x) + cos (13x) 169 What is I3? 3 - sin (13x) + 169 6 cos (13x) cos (13x) æ sin (13x) 2197 13 28561 1 -2³ sin (13x) + 169 3 -x² cos (13x) 169 x sin (13x) 2197 -cos (13x) 28561 - sin (13x) – 13 3 -x² cos (13x) + 169 x sin (13x) 2197 6 cos (13x) 28561 1 æ sin (13x) + 2197 -a³ sin (13æ) 13 3 -x² cos (13x) 169 cos (13x) - - 28561
You found that the reduction formula of a certain integral is In = 180 (13x" sin (13x) + næ"-1 cos (13x) – n (n – 1) In-2] 169 1 and that I =R a sin (13x) + cos (13x) 169 What is I3? 3 - sin (13x) + 169 6 cos (13x) cos (13x) æ sin (13x) 2197 13 28561 1 -2³ sin (13x) + 169 3 -x² cos (13x) 169 x sin (13x) 2197 -cos (13x) 28561 - sin (13x) – 13 3 -x² cos (13x) + 169 x sin (13x) 2197 6 cos (13x) 28561 1 æ sin (13x) + 2197 -a³ sin (13æ) 13 3 -x² cos (13x) 169 cos (13x) - - 28561
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![You found that the reduction formula of a certain integral is
In
[132" sin (13r)+ næ"-1 cos (13æ) – n (n – 1) In-2]
169
1
e sin (13x) +
cos (13x)
169
and that I
What is I3?
3
6
13
x sin (13x)
2197
x³ sin (13x) +
x² cos (13x)
169
-cos (13x)
28561
1
3
6
sin (13x) +
169
cos (13x)
x sin (13x)
2197
-cos (13x)
28561
169
1
3
x³ sin (13x)
13
6
-x sin (13x)
2197
cos (13x) +
cos (13x)
169
28561
6
1
-x³ sin (13x)
13
3
x sin (13x) +
2197
-cos (13x)
28561
-x² cos (13x)
169](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F850bafb9-4dc2-4f17-897a-2a1ced4c87ad%2Feb61d759-d1ea-4b13-8239-13ee4ee8a9fd%2Fooy5skn_processed.png&w=3840&q=75)
Transcribed Image Text:You found that the reduction formula of a certain integral is
In
[132" sin (13r)+ næ"-1 cos (13æ) – n (n – 1) In-2]
169
1
e sin (13x) +
cos (13x)
169
and that I
What is I3?
3
6
13
x sin (13x)
2197
x³ sin (13x) +
x² cos (13x)
169
-cos (13x)
28561
1
3
6
sin (13x) +
169
cos (13x)
x sin (13x)
2197
-cos (13x)
28561
169
1
3
x³ sin (13x)
13
6
-x sin (13x)
2197
cos (13x) +
cos (13x)
169
28561
6
1
-x³ sin (13x)
13
3
x sin (13x) +
2197
-cos (13x)
28561
-x² cos (13x)
169
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