You attach a meter stick to an oak tree, such that the top of the meter stick is 2.67 meters above the ground. Later, an acorn falls from somewhere higher up in the tree. If the acorn takes 0.191 seconds to pass the length of the meter stick, how high ho above the ground was the acorn before it fell, assuming that the acorn did not run into any branches or leaves on the way down? ho = m

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You attach a meter stick to an oak tree, such that the top of the meter stick is 2.67 meters above the ground. Later, an acorn falls
from somewhere higher up in the tree. If the acorn takes 0.191 seconds to pass the length of the meter stick, how high ho above
the ground was the acorn before it fell, assuming that the acorn did not run into any branches or leaves on the way down?
ho =
m
Transcribed Image Text:You attach a meter stick to an oak tree, such that the top of the meter stick is 2.67 meters above the ground. Later, an acorn falls from somewhere higher up in the tree. If the acorn takes 0.191 seconds to pass the length of the meter stick, how high ho above the ground was the acorn before it fell, assuming that the acorn did not run into any branches or leaves on the way down? ho = m
Expert Solution
Step 1

A meter stick is attached to the oak tree, such that its top is at a height of 2.67 m from the ground

An acorn falls from this tree, at some height above the meter stick. As it passes the entire length of the meter stick, it takes a time of 0.191 seconds.

As the acorn falls, it is continuously acted upon by gravity and hence it falls with an acceleration equal to acceleration due to gravity.

This problem can be solved by the use of the following kinematical equations

v=u+atv2=u2+2ass=ut+12at2u is the initial velocityv is the final velocity after time ts is the distance travelled in time ta is the acceleration

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