You are writing a program for a scientific organization that is trying to determine the coefficient of linear expansion of nickel experimentally (how much a bar of this met expands when heated.) The formula being used is as follows: coefficientNi = changelnLength/(initialLength * changelnTemp) Each experiment is given an ID number. The scientist will enter the ID number, the changelnLength in mm, the initialLength in mm, and the change in Temp in °C. You w calculate the coefficient based on the above formula, saving the ID number and the coefficient in a single Double ArrayList. Note that you do not need to understand what a coefficient of linear expansion is to do this project. You are given the formula to use and the variables you will need. Ju work the problem from a programmer's point of view. The program will need at least the following methods. The only global variable allowed is a Scanner object. • public static void main(String[] args) controls the flow of the program and manages the Double ArrayList. It will present the user with the choice to enter a new experiment, view experiment statistics, or exit the program. If an invalid choice is made, it should just repeat the menu of choices. • public static void getExperimentld(ArrayList data) asks the user for the ID of the experiment they're reporting on, checks to make sure that ID has not already been entered, and adds the ID to the ArrayList. It should bulletproof input and allow the user to keep trying until a unique ID is entered. (Note: the ID can ha

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You are writing a program for a scientific organization that is trying to determine the coefficient of linear expansion of nickel experimentally (how much a bar of this metal
expands when heated.) The formula being used is as follows:
coefficientNi = changelnLength/(initialLength * changelnTemp)
Each experiment is given an ID number. The scientist will enter the ID number, the changelnLength in mm, the initialLength in mm, and the change in Temp in °C. You will
calculate the coefficient based on the above formula, saving the ID number and the coefficient in a single Double ArrayList.
Note that you do not need to understand what a coefficient of linear expansion is to do this project. You are given the formula to use and the variables you will need. Just
work the problem from a programmer's point of view.
The program will need at least the following methods. The only global variable allowed is a Scanner object.
• public static void main(String[] args) controls the flow of the program and manages the Double ArrayList. It will present the user with the choice to enter a new
experiment, view experiment statistics, or exit the program. If an invalid choice is made, it should just repeat the menu of choices.
• public static void getExperimentld(ArrayList<Double> data) asks the user for the ID of the experiment they're reporting on, checks to make sure that ID has not
already been entered, and adds the ID to the ArrayList. It should bulletproof input and allow the user to keep trying until a unique ID is entered. (Note: the ID can have
a decimal point in it.)
• public static double calcCoefficient() calculates the coefficient of linear expansion, prompting the user for the initial length (mm), change in length (mm), and change in
temperature (°C), as needed for the formula. All of these values should allow decimal points and positive or negative values. If a non-numeric value is entered, you may
simply start over with the prompts for this data.
• public static void displayStats(ArrayList<Double> data) reads all the data stored in the ArrayList, prints out the entire list of experiment IDs and coefficients, followed
by the average value of the coefficient calculated so far, and how close that average is to the currently accepted value of 13 x 10-6/°C (0.000013) using the difference
between the two values.
Transcribed Image Text:You are writing a program for a scientific organization that is trying to determine the coefficient of linear expansion of nickel experimentally (how much a bar of this metal expands when heated.) The formula being used is as follows: coefficientNi = changelnLength/(initialLength * changelnTemp) Each experiment is given an ID number. The scientist will enter the ID number, the changelnLength in mm, the initialLength in mm, and the change in Temp in °C. You will calculate the coefficient based on the above formula, saving the ID number and the coefficient in a single Double ArrayList. Note that you do not need to understand what a coefficient of linear expansion is to do this project. You are given the formula to use and the variables you will need. Just work the problem from a programmer's point of view. The program will need at least the following methods. The only global variable allowed is a Scanner object. • public static void main(String[] args) controls the flow of the program and manages the Double ArrayList. It will present the user with the choice to enter a new experiment, view experiment statistics, or exit the program. If an invalid choice is made, it should just repeat the menu of choices. • public static void getExperimentld(ArrayList<Double> data) asks the user for the ID of the experiment they're reporting on, checks to make sure that ID has not already been entered, and adds the ID to the ArrayList. It should bulletproof input and allow the user to keep trying until a unique ID is entered. (Note: the ID can have a decimal point in it.) • public static double calcCoefficient() calculates the coefficient of linear expansion, prompting the user for the initial length (mm), change in length (mm), and change in temperature (°C), as needed for the formula. All of these values should allow decimal points and positive or negative values. If a non-numeric value is entered, you may simply start over with the prompts for this data. • public static void displayStats(ArrayList<Double> data) reads all the data stored in the ArrayList, prints out the entire list of experiment IDs and coefficients, followed by the average value of the coefficient calculated so far, and how close that average is to the currently accepted value of 13 x 10-6/°C (0.000013) using the difference between the two values.
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