You are trying to push your stalled car. Although you apply a horizontal force of 400 N to thecar, it doesn't budge, and neither do you. Which force(s) must also have a magnitude of 400 N?The friction force exerted by the road on you.The normal force exerted by the road on you.O The force exerted by the car on you.O The gravity force exerted by the car on the road. Vector A is 6.8 units in magnitude moving to the right while Vector B is 5.5 units in magnitudemoving to the left. Determine Vector C if: C=A+B and C = A - BO -1.3 /-12.3O 12.3/1.3O 1.3/ 12.312.3/-1.3

A horizontal force of 400 N is being applied on the car, in order to make it move. As mentioned, the…

Answered: You are trying to push your stalled…

Similar questions

The net force on a mass is zero. Which ONE of the following must be TRUE? The mass must be at rest. The speed of the mass is constant but the direction of motion may be changing. Both the speed and the direction of motion of the mass may be changing. The direction of motion of the mass is constant but the speed may be changing. O The velocity of the mass is constant.
The net force on an object is in the positive x-direction. Consider the following statements. (i) The object can be moving in the negative x-direction. (ii) The object can be speeding up. (iii) The object can be slowing down. (iv) The object can be moving in the positive y-direction. (i) and (ii) (ii) and (iii) (iii) and (iv) all the statements are true.
A block m, rests on a surface. A second block m₂ sits on top of the first block. A horizontal force F applied to the bottom block pulls both blocks at constant velocity. Here m₁ = m₂ = m. m₂ my necessary.) (a) What is the normal force exerted by the surface on the bottom block? (Use the following as necessary: m and g as N₁ = (b) What is the normal force exerted by the bottom block on m₂? (Use the following as necessary: m and g as necessary.) N₂ = (c) How would your answers to parts (a) and (b) change if m₁ = 7m and m₂ ON₁ = 3.5mg, N₂ = 3.5mg ON₁ = 8mg, N₂ = mg ON₁ = 8mg, N₂ = 7mg ON₁ = 6mg, N₂ = 5.25mg (d) How would your answers to parts (a) and (b) change if m₁ = m and m₂ = 7m? H mg ON₁ = 8mg, N₂ ON₁ = 6mg, N₂ = 5.25mg ON₁ = 8mg, N₂ = 7mg ON₁ = = 3.5mg, N₂ 3.5mg, N₂ = 3.5mg 16 :9: esc F1 Q 2 F2 W #3 APR 28 00 20 F3 E 6000 $ 4 F4 R 45 % F5 T 16 ali MacBook Air F6 6 Y & 7 JA F7 D 8 DII
3q
Is it possible for an object at rest to have only a single force actingon it? If your answer is yes, provide an example. If your answer isno, explain why not.
Suppose one's hand exerts a force of 15 N upward on a book weighing 12 N. The reaction to the force of the hand on the book is a force of12 N exerted by the book on the hand.3 N exerted by the book on the hand. 15 N exerted by the book on the hand.12 N exerted by the book on the Earth.10 N exerted by the Earth on the book.
While passing a slower car on a busy highway, you accelerate your 1500 kg car from 17.0 m/s to 90.0 km/h in 15.0 s.(i). What is the force of the car? (ii). How far have you traveled in 20 s?
Let's consider two vectors, A = (-7, 10), B = (-5, -8), and C = (-1, 6) as shown below. A C B What is the magnitude of A+ B+ C? Answer What is the direction (8) of A+B+C relative to +x-axis? a-839 b. 20 C-85 3 d. 148°
Multiple-object systems without friction: Three objects are connected by massless wires over a massless frictionless pulley as shown in the figure. The tension in the wire connecting the 10.0-kg and 15.0-kg objects is measured to be 133 N. What is the mass M? (52.8 kg) Σ 15.00 kg 133 N 10.00 kg
Please help me on sixth question according table and figure. Solve it using vectors.
An object rests on a horizontal frictionless surface. A horizontal force of magnitude F is applied. This force produces an acceleration: O only if F is larger than the weight of the object. O only while the object suddenly changes from rest to motion. O always. O only if the inertia of the object decreases. Onone of the given choices
Consider the following statement: “The normal force on an object is always equal to the weight of the object.”Select all the reasons that this statement is false . The normal force is not always parallel to the force of gravity The normal force is independent of the force of gravity The normal force is only equal to the weight of the object when sitting on a horizontal surface and there are no other forces in the y-direction except gravity The normal force causes an acceleration and therefore does not interact with gravity