Ex.3: determine the magnitude of forces FA and FB acting on each chain In order to develop a resultant force of 600 N directed along the positive Y-axis. Sol.: FB FA 30° 600 F-439 N As 45 sin 105 600 = 311 N Ams sin 105 F-GOON

Ex.3: determine the magnitude of forces FA and FB acting on each chain In order to develop a resultant force of 600 N directed along the positive Y-axis. Sol.: FB FA 30° 600 F-439 N As 45 sin 105 600 = 311 N Ams sin 105 F-GOON

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Description: Ex.3: determine the magnitude of forces FA and FB acting on each chain In orderto develop a resultant force of 600 N directed along the positive Y-axis.Sol.:yFA30600F- 439 NAasa 45 sia 105600F 311 NAms105-60ON

Physics for Scientists and Engineers, Technology Update (No access codes included)

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ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter5: The Laws Of Motion

Section: Chapter Questions

Problem 5.53P: Review. A rifle bullet with a mass of 12.0 g traveling toward the right at 260 m/s strikes a large...

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Ex.3: determine the magnitude of forces FA and FB acting on each chain In order
to develop a resultant force of 600 N directed along the positive Y-axis.
Sol.:
y
FA
30
600
F- 439 N
Aas
a 45 sia 105
600
F 311 N
Ams
105
-60ON

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