You are planning a deep space exploration and want to take your cat with you. If your spacecraft achieves a maximum speed of 87% of the speed of light, how much addit
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You are planning a deep space exploration and want to take your cat with you. If your spacecraft achieves a maximum speed of 87% of the
Assume you start from zero velocity and your magical cat does not require additional food or litter. The cat weighs 8.5 lbf. Use 3 × 10^8 m/s for the speed of light.
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- The escape velocity from a massive object is the speed needed to reach an infinite distance from it and have just slowed to a stop, that is, to have just enough kinetic energy to climb out of the gravitational potential well and have none left. You can find the escape velocity by equating the total kinetic and gravitational potential energy to zero E = = muesc - GmM/r=0 Vesc = √2GM/r where G is Newton's constant of gravitation, M is the mass of the object from which the escape is happening, and r is its radius. This is physics you have seen in the first part of the course, and you should be able to use it to find an escape velocity from any planet or satellite. For the Earth, for example the escape velocity is about 11.2 km/s, and for the Moon it is 2.38 km/s. A very important point about escape velocity: it does not depend on what is escaping. A spaceship or a molecule must have this velocity or more away from the center of the planet to be free of its gravity, 1. In the atmosphere of…A planet has a radius of 4.00 x 10^6 m, and rotates so rapidly that an object on the equator feels only 10% of the weight that it feels at the poles. What is the speed of an object at the equator?A 200.0 kg rocket is launched directly upward from Earth at 9.00 km/s (rE = 6.38 x 10^6 m,mE = 5.98 x 10^24 kg, G = 6.67 x 10^-11)a) What altitude above Earth’s surface does the rocket reach? b) What is the binding energy at that altitude?
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