You are learning in archery class that to hit the bullseye (the center of the target) you need to aim a bit above it. The day of the test you are given a target that is a distance d = 40 m away, and it can move along a rail on the floor, coming towards you at a constant speed of u = m/s. You prepare your bow and arrow in such a way that the arrow will fly off from the same height above the ground as the bullseye (h = 1.4 m). = 0.5

Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter6: Motion In Two Dimensions
Section: Chapter Questions
Problem 84A
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You are learning in archery class that to hit the bullseye (the center of the target) you need to
aim a bit above it. The day of the test you are given a target that is a distance d
40 m away,
and it can move along a rail on the floor, coming towards you at a constant speed of || = 0.5
m/s. You prepare your bow and arrow in such a way that the arrow will fly off from the same
height above the ground as the bullseye (h 1.4 m).
S
h
15
7
So
d
=
ū
h
If you shoot the arrow with initial speed |vi|
30 m/s, how high should you aim so you can hit
the moving bullseye? In other words, find the value (in degrees) for the angle in the
diagram. Assume there is no air resistance and that this is happening on Earth. The following
trigonometric identity may be useful to you: sin(20) = 2 sin cos
Transcribed Image Text:- You are learning in archery class that to hit the bullseye (the center of the target) you need to aim a bit above it. The day of the test you are given a target that is a distance d 40 m away, and it can move along a rail on the floor, coming towards you at a constant speed of || = 0.5 m/s. You prepare your bow and arrow in such a way that the arrow will fly off from the same height above the ground as the bullseye (h 1.4 m). S h 15 7 So d = ū h If you shoot the arrow with initial speed |vi| 30 m/s, how high should you aim so you can hit the moving bullseye? In other words, find the value (in degrees) for the angle in the diagram. Assume there is no air resistance and that this is happening on Earth. The following trigonometric identity may be useful to you: sin(20) = 2 sin cos
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