You are given the following half-reactions. AgCl(s) + e → Ag(s) + Cl - (aq) صلح = +0.22 V Ag+ (aq) + e Ag(s) Construct a cell with the following cell reaction. AgCl(s) → Ag+ (aq) + Cl - (aq) (a) What is the standard cell potential? 4.0 -.58 = +0.80 V (b) What is the value of AG for the reaction? 4.0 56 kJ/mol (c) What is the equilibrium constant as determined from the cell potential? (Please recall that often a significant figures appears to be lost when raising 10 to a power.) 4.0 1.59e-10 x

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**Electrochemistry Tutorial: Calculating Cell Potentials**

In this exercise, we explore the construction of a cell from given half-reactions and calculate various thermodynamic properties.

**Given Half-Reactions:**

1. \( \text{AgCl}(s) + e^- \rightarrow \text{Ag}(s) + \text{Cl}^-(aq) \)   
   \( E^\circ = +0.22\, \text{V} \)

2. \( \text{Ag}^+(aq) + e^- \rightarrow \text{Ag}(s) \)  
   \( E^\circ = +0.80\, \text{V} \)

**Construct a Cell with the Following Reaction:**

\[ \text{AgCl}(s) \rightarrow \text{Ag}^+(aq) + \text{Cl}^-(aq) \]

### Questions:

**(a) What is the standard cell potential?**

- Calculated \( E^\circ \) value: **0.58 V** (correct).

**(b) What is the value of \( \Delta G^\circ \) for the reaction?**

- Calculated \( \Delta G^\circ \): **56 kJ/mol** (correct).

**(c) What is the equilibrium constant as determined from the cell potential?**

- Attempted equilibrium constant \( K \): **1.59e-10** (incorrect). 
- Note: There is a reminder regarding potential loss of significant figures when raising numbers to a power of ten.

**Explanation:**

The standard cell potential (\( E^\circ \)) is the difference between the standard reduction potentials of the cathode and anode. In this activity, values were calculated to enhance understanding of thermodynamic properties and equilibrium as related to redox reactions. A discrepancy was noted in the equilibrium constant calculation, emphasizing the need to carefully consider significant figures in such calculations.
Transcribed Image Text:**Electrochemistry Tutorial: Calculating Cell Potentials** In this exercise, we explore the construction of a cell from given half-reactions and calculate various thermodynamic properties. **Given Half-Reactions:** 1. \( \text{AgCl}(s) + e^- \rightarrow \text{Ag}(s) + \text{Cl}^-(aq) \) \( E^\circ = +0.22\, \text{V} \) 2. \( \text{Ag}^+(aq) + e^- \rightarrow \text{Ag}(s) \) \( E^\circ = +0.80\, \text{V} \) **Construct a Cell with the Following Reaction:** \[ \text{AgCl}(s) \rightarrow \text{Ag}^+(aq) + \text{Cl}^-(aq) \] ### Questions: **(a) What is the standard cell potential?** - Calculated \( E^\circ \) value: **0.58 V** (correct). **(b) What is the value of \( \Delta G^\circ \) for the reaction?** - Calculated \( \Delta G^\circ \): **56 kJ/mol** (correct). **(c) What is the equilibrium constant as determined from the cell potential?** - Attempted equilibrium constant \( K \): **1.59e-10** (incorrect). - Note: There is a reminder regarding potential loss of significant figures when raising numbers to a power of ten. **Explanation:** The standard cell potential (\( E^\circ \)) is the difference between the standard reduction potentials of the cathode and anode. In this activity, values were calculated to enhance understanding of thermodynamic properties and equilibrium as related to redox reactions. A discrepancy was noted in the equilibrium constant calculation, emphasizing the need to carefully consider significant figures in such calculations.
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