You are given a set of data (xj, y¡) for linear regression analysis and find out these data are not linearly related by plotting (xị, Yi) with graphical analysis. After using transformation of data from (x¡ , yi) to (X¡ = log x¡ , Y¡ = log y¡ ) and a linear fitting line were derived, Y = A + BX , for the power-law relationship y = k x". You tried the power-law equation's k and n by transforming back from A and B in that linear relation equation Y = A + B X. Which one of the below can be the correct resul There might be more than one correct answer; please select all of the correct answers. O logA=k

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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You are given a set of data (xj, Yi) for linear regression analysis and find out these data are not linearly related by plotting (x¡, Yi) with graphical analysis. After using log
transformation of data from (x¡ , yi) to (X¡ = log X¡ , Y¡ = log yi ) and a linear fitting line were derived, Y = A + BX, for the power-law relationship y = k x". You tried to find
the power-law equation's kand n by transforming back from A and B in that linear relation equation Y = A + BX. Which one of the below can be the correct result?
There might be more than one correct answer; please select all of the correct answers.
O logA=k
O n= logB
O 10A=K
O en=B
n = B
O A=logK
O eK=A
O eB=n
Transcribed Image Text:You are given a set of data (xj, Yi) for linear regression analysis and find out these data are not linearly related by plotting (x¡, Yi) with graphical analysis. After using log transformation of data from (x¡ , yi) to (X¡ = log X¡ , Y¡ = log yi ) and a linear fitting line were derived, Y = A + BX, for the power-law relationship y = k x". You tried to find the power-law equation's kand n by transforming back from A and B in that linear relation equation Y = A + BX. Which one of the below can be the correct result? There might be more than one correct answer; please select all of the correct answers. O logA=k O n= logB O 10A=K O en=B n = B O A=logK O eK=A O eB=n
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