You are given 3 identical capacitors with C = 1 µF each. Using only those capacitors, what is the ratio of the largest to smallest capacitance circuit you can create (Cmaz/Cmin)? (a) 1 (b) 3 (c) 6 (d) 9
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A: The correct answer is option (2) i.e. 1.475 x 10-6 J
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A: C1 = 51.2 pF C2 = 27.4 pF C3 = 71.1 pF
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Q: Three capacitors have capacitances 20.0 μF, 30.0 µF, and 40.0 µF. What is their effective…
A: Solution:-Given thatC1=20 μFC2=30 μFC3=40 μF
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A: C1 = 12.3 μF V = 353 volts Q = 1.37 mC
Q: Plot 1 in Figure (a) gives the charge q that can be stored on capacitor 1 versus the electric…
A: qs = 12 uCVs = 6 VV = 7.5 V
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A: Given: Let capacitor C1 = C2 = 5 pF be in parallel. Let C3 = 5 pF , C4 = 10 pF , C5 = 15 pF ,…
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A: Given: Potential Difference,V=9VCapacitor 1,C1=2.2μF=2.2×10-6FCapacitor 2,C2=9.05μF=9.05×10-6F When…
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A: Given that: The capacitance is: C1=4.50 μFC2=7.50 μFC3=2.50 μFC4=4.50 μF The voltage is V0=20.0 V…
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Q: For the image shown, the capacitors have the following values: C1C1 = 3.6*10^-6, C2C2 = 5.95*10^-6,…
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Q: Two capacitors, C1 = 5.92 µF and C2 = 3.30 µF, are connected in parallel, then the combination is…
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A: solution is given as
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Q: Plot 1 in Figure (a) gives the charge q that can be stored on capacitor 1 versus the electric…
A: It is given that, We can find the capacitance of a capacitor using the following formula.C -…
Q: In this figure, C1= 9.5 μF, C2= 3.3 μF, C3= 4.3 μF. The equivalent capacitance of the combination is…
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Q: Two capacitors of capacitance C₁ = 100 nF and C₂ = 5 µF are connected in series across a cell with…
A: The capacitance of the two capacitors: C1 = 100 nF = 100 x 10-9 F and C2 = 5 μF = 5 x 10-6 F The…
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- Four capacitors are connected as shown. (a) Find the equivalent capacitance between points a and b. (b) Calculate the charge on each capacitor, taking ΔVab = 15.0 V.Two capacitors of capacitance C1 = 100 nF and C2 = 5 μF are connected in series across a cell with emf V = 5V. What is the voltage across C2?The capacitive network shown in the figure is assembled with initially uncharged capacitors. A potential difference, Vab = +100V, is applied across the network. The switch S in the network is initially open but is then closed. Assume that all the capacitances shown are accurate to two significant figures. What is the equivalent capacitance between ab a) With the switch S open? b) With the switch S closed? A) (a) 14 micro-Farad; (b) 17 micro-Farad B) (a) 11 micro-Farad; (b) 17 micro-Farad C) (a) 8 micro-Farad; (b) 71 micro-Farad D) (a) 99 micro-Farad; (b) 67 micro-Farad E) (a) 4 micro-Farad; (b) 7 micro-Farad
- Q.4: Four capacitors are arranged in the following configuration: the capacitances of capacitors are Ci= 1.5µF, C2= 3.5µF, C3= 2.0µuF, C4= 2.5µF, Cs= 3.0µF and Cs=4.0µF. The voltage V of the battery is 12.0V. (a) Calculate the capacitance of the configuration. (b) How much energy is stored in the configuration? (c) How much energy is stored in capacitor C1? C2Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius ry has charge -Q. The electric field E at a radial distance r from the central axis is given by the function: E = aer/a0 + B/r + bo where alpha (a), beta (8), an and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Vah between the two conductors. The potential difference is related to the electric field by: Vah = Edr= - Fdr Calculating the antiderivative or indefinite integral, Vab = (-aager/a0 +8 + bo By definition, the capacitance Cis related to the charge and potential difference by: C = Evaluating with the upper and lower limits of integration for Vab, then simplifying: C= Q/( (e"b/a0 .eralao) + B In( )+ bo ( ))Two capacitors, C1 = 5.92 µF and C2 = 3.30 µF, are connected in parallel, then the combination is connected to a 250 V battery. When the capacitors are charged, each one is removed from the circuit. Next, the two charged capacitors are connected to each other so that the positive plate of one capacitor is connected to the negative plate of the other capacitor. What is the resulting charge on each capacitor (in µC)? q′1= 421 µC q′2= 234 µC (b) What If? What is the resulting charge on each capacitor (in µC) if they are instead charged as a series combination and then connected positive plate to positive plate and negative plate to negative plate? q′1= q′2= solved the first two I need help with the bottom two it has to be in the format of the first two thank you
- The total capacitance of three capacitors connected in series is equal to 6.25 μF . Two of the three capacitors have the following capacitance values, 25 μF and 50 μF while the other one is to be determined. If the three capacitors are connected in parallel , calculate the total capacitance of the parallel combination. Express the answer in Farad (F) using scientific notation.A cylindrical capacitor has radii a = 0.27 cm and b = 0.37 cm, as in the figure. Find the radius r such that the fraction of the total energy that is within a cylinder of radius r is 0.60.Calculate the equivalent capacitance for the configurations Y and Z which are shown below. The values of the capacitances in the figure are in µ F. Then rank X, Y, and Z in order of INCREASING equivalent capacitance. 13.0 10.8 6.3 3.8 37.0 X' Y' Z* Smallest capacitance has rank 1, largest capacitance has rank 3. 1 The rank of X is ... 3 The rank of Y is ... 2 The rank of Z is ... Submit Answer Incorrect. Tries 3/5 Previous Tries
- EMF = Vo = 6 volts. and C = 5 μF Calculate the theoretical value of the charge (q) in the capacitor during charging at t = RC. Use equation 3.What is the equivalent capacitance of a 1 Farad capacitor and a 0.5 Farad capacitor in series?A capacitor (C=540 microF) has a potential deltaV= 80 volts across it. How much energy is stored in the capacitor?