Two capacitors, C1 = 5.92 µF and C2 = 3.30 µF, are connected in parallel, then the combination is connected to a 250 V battery. When the capacitors are charged, each one is removed from the circuit. Next, the two charged capacitors are connected to each other so that the positive plate of one capacitor is connected to the negative plate of the other capacitor. What is the resulting charge on each
Two capacitors, C1 = 5.92 µF and C2 = 3.30 µF, are connected in parallel, then the combination is connected to a 250 V battery. When the capacitors are charged, each one is removed from the circuit. Next, the two charged capacitors are connected to each other so that the positive plate of one capacitor is connected to the negative plate of the other capacitor. What is the resulting charge on each
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Two capacitors, C1 = 5.92 µF and C2 = 3.30 µF, are connected in parallel, then the combination is connected to a 250 V battery. When the capacitors are charged, each one is removed from the circuit. Next, the two charged capacitors are connected to each other so that the positive plate of one capacitor is connected to the negative plate of the other capacitor. What is the resulting charge on each capacitor (in µC)?
q′1= 421 µC
q′2= 234 µC
(b)
What If? What is the resulting charge on each capacitor (in µC) if they are instead charged as a series combination and then connected positive plate to positive plate and negative plate to negative plate?
q′1=
q′2=
q′2=
solved the first two I need help with the bottom two it has to be in the format of the first two thank you
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