You are employed at an insurance company and are asked to calculate the probabilities of various financial losses due to hurricanes. Typically hurricanes tend to cause $10 billion worth of losses (i.e. claims) with a standard deviation of 4 billion and these losses are normally distributed. D) what amount of losses would put a hurricane in the top 1% of losses?

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You are employed at an insurance company and are asked to calculate the probabilities of various financial losses due to hurricanes. Typically hurricanes tend to cause $10 billion worth of losses (i.e. claims) with a standard deviation of 4 billion and these losses are normally distributed. D) what amount of losses would put a hurricane in the top 1% of losses?
(D) What amount of losses would put a hurricane in the top 1% of losses?
For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac).
BIUS
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medium
E vE v
A v v
工 厄 Q5d
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田田田国
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X-Normal(mean=10,standard deviation=4)
A) P(4<X<12)=P((4-10)/4<(X-µ)/o<(12-10)/4)
=P(-1.5<z<0.5)=0.6247
I
B) P(x<1)=P((X-µ)/o<(1-10)4)
P(z<-2.25)=0.0122
C) P(x>20)=P((X-µY>(20-10)/4))
P(z>2.5)=0.0062
Number=100×P(x>20)=100×0.0062=0.62|
Transcribed Image Text:(D) What amount of losses would put a hurricane in the top 1% of losses? For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph medium E vE v A v v 工 厄 Q5d Source Sans P. v 田田田国 田用国 <》言() X-Normal(mean=10,standard deviation=4) A) P(4<X<12)=P((4-10)/4<(X-µ)/o<(12-10)/4) =P(-1.5<z<0.5)=0.6247 I B) P(x<1)=P((X-µ)/o<(1-10)4) P(z<-2.25)=0.0122 C) P(x>20)=P((X-µY>(20-10)/4)) P(z>2.5)=0.0062 Number=100×P(x>20)=100×0.0062=0.62|
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