You are dealt 5 cards from a standard 52 card deck (order doesn't matter and without replacement). All 5 cards have distinct numbers/faces. You discard two cards and return them to the deck, and then draw two more from the remaining deck (order doesn't matter and without replacement). How many ways are there so that your final hand contains one pair? (Pair: two cards with the same number/face value, but different suits.) The answer is an integer. Thanks in advance!

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Answer the following question accordingly. Thanks in advance!

**Card Probability Problem**

You are dealt 5 cards from a standard 52-card deck (order doesn’t matter and without replacement). All 5 cards have distinct numbers/faces.

You discard two cards and return them to the deck, and then draw two more from the remaining deck (order doesn’t matter and without replacement).

How many ways are there so that your final hand contains one pair? (Pair: two cards with the same number/face value, but different suits.)

The answer is an integer.

Thanks in advance!
Transcribed Image Text:**Card Probability Problem** You are dealt 5 cards from a standard 52-card deck (order doesn’t matter and without replacement). All 5 cards have distinct numbers/faces. You discard two cards and return them to the deck, and then draw two more from the remaining deck (order doesn’t matter and without replacement). How many ways are there so that your final hand contains one pair? (Pair: two cards with the same number/face value, but different suits.) The answer is an integer. Thanks in advance!
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