You are conducting a test of the claim that the row variableand the column variable are dependent in the followingcontingency table.XYZA 28 41 33B 31 21 32Give all answers rounded to 2 places after the decimalpoint, if necessary.(a) Enter the expected frequencies below:XZABY(b) What is the chi-square test-statistic for this data?Test Statistic: x²==(c) What is the p-value for this test of independenceP-Value:

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Answered: You are conducting a test of the claim…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Carboxyhemoglobin is formed when hemoglobin is exposed to carbon monoxide. Heavy smokers tend to have a high percentage of carboxyhemoglobin in their blood.t Let x be a random variable representing percentage of carboxyhemoglobin in the blood. For a person who is a regular heavy smoker, x has a distribution that is approximately normal. A random sample of n = 12 blood tests given to a heavy smoker gave the following results (percent carboxyhemoglobin in the blood). Note: For degrees of freedom d.f. not in the Student's t table, use the closest d.f. that is smaller. In some situations, this choice of d.f. may increase the P-value a small amount and thereby produce a slightly more "conservative" answer. 9.1 9.8 10.4 9.8 11.3 12.2 11.6 10.3 8.9 9.7 13.4 9.9 (a) Use your calculator to calculate x and s. (Round your answers to four decimal places.) X = S = (b) A long-term population mean u = 10% is considered a health risk. However, a long-term population mean above 10% is considered a…
The cross-tabulation data given below represent the number of males and females in a work group who feel overstressed and those who don't. Complete parts a through d below. Overstressed? Female Male No Yes 10 6 5 11 a. Write the hypotheses for the chi-square test for independence. Ho gender and overstress are independent H₁ gender and overstress are dependent b. Find the expected frequencies. Overstressed? Female Male Grand Total No 7.5 7.5 15 Yes 8.5 8.5 17 Grand Total 16 16 32 (Type integers or decimals rounded to two decimal places as needed.) c. Compute the chi-square statistic 3.14 (Type an integer or decimal rounded to two decimal places as needed.) d. Find the chi-square critical value and p-value and draw a conclusion using a level of significance of 0.05. Find the chi-square critical value (Round to three decimal places as needed.) ad
The mean of X is 5 and its SD is 3. The Mean of Y is -2 and its SD is 6. You are now being told they are independent. Find the value of each requested parameter A. The mean of T= -3x +20 is ___ B. The mean of W= Y - X is ___ C. The variance of D = X - 2Y is ___
A popular theory is that presidential candidates have an advantage if they are taller than their main opponents. Listed are heights (in centimeters) of randomly selected presidents along with the heights of their main opponents. Complete parts (a) and (b) below. 191 175 173 191 190 175 181 165 184 193 185 Height (cm) of President Height (cm) of Main Opponent 178 C... Since the P-value is greater than the significance level, fail to reject the null hypothesis. There is not sufficient evidence to support the claim that presidents tend to be taller than their opponents. b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature of the confidence interval leads to the same conclusion reached in part (a)? The confidence interval is cm<< cm. (Round to one decimal place as needed.) What feature of the confidence interval leads to the same conclusion reached in part (a)? Since the confidence interval contains zero fail to reiect the null…
Q1.2 Mean of X A medical practice collects data on its patients with respect to several personal habits. The following table gives the distribution of the number of alcoholic drinks consumed per day in that population of patients. X = # of drinks per day Probability Save Answer Q1.3 Variance of X X = # of drinks per day Probability 0 0.38 Find the mean for this random variable, that is find ux. Show your work in the space below. Save Answer A medical practice collects data on its patients with respect to several personal habits. The following table gives the distribution of the number of alcoholic drinks consumed per day in that population of patients. 0 0.38 Q1.4 Standard Deviation of X X = # of drinks per day Probability 1 0.32 0 0.38 1 0.32 2 0.25 Find the variance for this random variable, that is find (ox)². Only show the first and last term of the work required. 1 2 0.25 A medical practice collects data on its patients with respect to several personal habits. The following table…
Fill this table with the missing columns: Interval Frequency Probability Probability Density 1 3 13 4 - 6 15 7-9 19 9 - 11 14 11-16 17 - 26 3
J sampled 1000 people, and determined whether they are a teacher or not and their gender. J found the information in the following table. Is an Teacher Isn't an Teacher Male 42 449 Female 5 488 Other 1 15 Perform a chi-squared test of independence to test the null hypothesis that gender and status as an teacher are independent versus the alternative that they are dependent. What is the p-value for this test? What are the steps to come to this conclusion?
Researchers conducted a study to determine whether magnets are effective in treating back pain. Pain was measured using the visual analog scale, and the results shown below are among the results obtained in the s Higher scores correspond to greater pain levels. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) to (c) below. Reduction in Pain Level After Magnet Treatment (u): n=15, x=0.45, s=1.02 Reduction in Pain Level After Sham Treatment (H2): n = 15, x=0.38, s = 1.55 a. Use a 0.01 significance level to test the claim that those treated with magnets have a greater mean reduction in pain than those given a sham treatment (similar to a placebo). What are the null and alternative hypotheses? OA. Ho: H1 H2 H₁₁ 2H2 OC. Ho: HH2 H₁: H₁

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