10:25PM Sat1009A myopenmath.comBased on the hypotheses, find the following:Test StatisticCritical-value%3DShade the sampling distribution curve with the correct critical value(s) and shade the critical regions. Thearrows can only be dragged to t-scores that are accurate to 1 place after the decimal point (these valuescorrespond to the tick marks on the horizontal axis). Select from the drop down menu to shade to the left, tothe right, between or left and right of the t-score(s).Shade: Left of a valueClick and drag the arrows to adjust the values.-4-3-2-134-1.3The correct decision is to | Select an answerThe correct summary would be: select an answerthat the population meandoctor's salary (in thousands of dollars) is significantly more than 88.Question Help: Message instructorSubmit Question 10:25 PM Sat Dec 12100% )A myopenmath.comYou are conducting a study to see if the mean doctor's salary (in thousands of dollars) is significantly morethan 88. A random sample of 26 doctors' salary in thousands of dollars is shown below. Test the claim using a1% level of significance. Give answer to at least 4 decimal places.Salary90.0793.2786.6592.5287.1190.8891.4394.5889.5383.5286.0484.1789.2278.4492.0680.0292.2381.12102.3496.9698.294.3582.3692.5786.3592.32What are the correct hypotheses?Ho: Select an answer?thousand dollarsH1:Select an answerthousand dollars

Let μ denotes the population mean doctor's salary. The clam of the test is that the mean doctor's salary is significantly more than 88. The hypothesis is, Null hypothesis: H0:μ≤88 thousand dollars Alternative hypothesis: H1:μ>88 thousand dollars The descriptive statistics is conducted using EXCEL. The software procedure is given below: Enter the data. Select Data > Data Analysis >Descriptive Statistics> OK. Enter Input Range as Salary column. Mark Labels in First Row. Mark Summary Statistics. Click OK. The output using EXCEL is as follows: From the output, the mean is 89.5504, and the standard deviation is 5.7949.The test statistic is, t=x¯-μsn=89.5504-885.794926=1.55041.1364734=1.3642 Thus, the test statistic is 1.3642. The degrees of freedom is, df=n-1=26-1=25 The degrees of freedom is 25. The significance level is 0.01, then the right tailed area is 0.99. Computation of critical value: The critical value of t-distribution for 0.99 area at 25 degrees of freedom can be obtained using the excel formula “=T.INV(0.99,25)”. The critical value is 2.4851. Thus, the critical value is 2.4851. The shaded area is right of a value, Decision rule: If test statistic > critical value, then reject the null hypothesis. Otherwise, do not reject the null hypothesis. Conclusion: The test statistic (1.3642) is less than the critical value (2.4851). Based on decision rule, fail to reject the null hypothesis. Thus, it cannot be concluded that the population mean doctor's salary is significantly more than 88.

Math

Statistics

You are conducting a study to see if the mean doctor's salary (in thousands of dollars) is significantly more than 88. A random sample of 26 doctors' salary in thousands of dollars is shown below. Test the claim using a 1% level of significance. Give answer to at least 4 decimal places.

You are conducting a study to see if the mean doctor's salary (in thousands of dollars) is significantly more than 88. A random sample of 26 doctors' salary in thousands of dollars is shown below. Test the claim using a 1% level of significance. Give answer to at least 4 decimal places.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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