A recent survey compared the costs of adoption through public and private agencies. For a sample of 16 adoptions through a publicagency, the mean cost was $21,045, with a standard deviation of $835. For a sample of 18 adoptions through a private agency, themean cost was $22,840, with a standard deviation of $1,545. Assume the sample populations do not have equal standard deviationsand use the 0.05 significance level.Required:a. Find the degrees of freedom for unequal variance test. (Round down your answer to the nearest whole number.)Degrees of freedomb. State the decision rule for 0.05 significance level: He: HPublic SHPrivate H₁: HPublic HPrivate (Round your answer to 3decimal places.)Reject Ho if tc. Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimalmiscar c. Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimalplaces.)Value of the test statisticd. Can we conclude the mean cost is larger for adopting children from a private agency?Ho Weconclude the mean cost is larger for adopting children from a private agency.

There are two independent samples which are public agency and private agency.We have to test whether…

Answered: A recent survey compared the costs of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A parent claims that children spend about 2 hours a day in front of computer screens. We think that the parent is underestimating the situation and does a survey of 25 children and finds a mean of 3.5 and sample standard deviation of 1.2 hours. Check the parents claim at the .05 level.
The average McDonald's restaurant generates $2.2 million in sales each year with a standard deviation of 0.9. Malik wants to know if the average sales generated by McDonald's restaurants in New Jersey is different than the worldwide average. He surveys 32 restaurants in New Jersey and finds the following data (in millions of dollars): 1, 1.2, 2.1, 2.8, 2.7, 1.5, 1.7, 3.5, 1.4, 3.6, 2.3, 2.8, 1.8, 2.1, 1.4, 2.1, 2.8, 2.1, 2.1, 2, 4.1, 3.1, 2.2, 3.7, 2.1, 2.4, 2.8, 1.1, 1.7, 2.2, 1.6, 3.4 Perform a hypothesis test using a 8% level of significance. Step 1: State the null and alternative hypotheses. Ho:?v|?く H。:?v||?く (So we will be performing a Select an answer v test.) Step 2: Assuming the null hypothesis is true, determine the features of the distribution of point estimates using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are Select an answer with distribution mean and distribution standard deviation Step 3: Find the p-value of the point…
Suppose the annual employer 401K cost per participant is normally distributed with a mean of $770. If 73.89% of such costs are greater than $370, what is the standard deviation of the annual employer 401K cost per participant?
Taking the family to an amusement park has become increasingly costly according to the industry publication Amusement Business, which provides figures on the cost for a family of four to spend the day at one of America's amusement parks. A random sample of 25 families of four that attended amusement parks yielded a sample mean of $232 and sample standard deviation of $42. A. What is the best point estimate for the average (mean) cost for a family of four to spend the day at an American amusement park? Round your answer to the nearest dollar. Point estimate: $ B. Obtain a 95% confidence interval for the mean cost for a family of four to spend the day at an American amusement park? Round your lower and upper limits to the nearest dollar. Confidence interval: $ to $ C. What is the margin of error for the 95% confidence interval found in part B? Round answer to the nearest
A quick survey of peanut butter prices had standard deviation and mean of $0.26 and $3.68, respectively. Compute the area for a peanut butter jar costing between $3.50 and $4.25.
A study of compulsive buying behavior conducted a national telephone survey in 2004 of adults aged 18 and over. The total credit card balance had a mean of $3,399 and standard deviation of $5,595 for 100 compulsive buyers and a mean of $2,837 and standard deviation of $6,335 for 1,682 other respondents. Estimate the difference between the sample means for compulsive buyers and other respondents, and find the standard error of the difference. Let mu1 = the population mean total credit card balance for non-compulsive buyers Let mu2 = the population mean total credit card balance for compulsive buyers y(bar)2-y(bar)1= Standard error of the difference =
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Suppose the average annual in-state tuition and required fees for public 4-year institutions follow a normal distribution with a population mean of $9,329 and a population standard deviation of $1865. What is the interquartile range of public 4- year institution cost? What cost would place a public 4-year institution into the lowest 10%?
According to the document Consumer Expenditures, the average consumer spent $1,874 on apparel and services in 2006. That same year, a sample of 25 consumers in the Northeast had a sample mean and standard deviation of $2,061 and $351, respectively. We are to conduct a hypotheses test to determine whether the 2006 mean annual expenditure on apparel and services for consumers in the Northeast differed from the national mean of $1,874. a. Test statistic isb. The ? − value of the test isc. At the significance level calculated in part b), we conclude that the mean annual expenditure on apparel and services for consumers in the Northeast is
. Average annual expense of a middle-income household living in Afghanistan is 360,000 Afghani with a standard deviation of 4,000 based on sample of 1,500 respondents. What is the range for annual expense for 93% of middle-income households in Afghanistan?
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The mean hourly wage for employees in goods-producing industries is currently $24.57 (Bureau of Labor Statistics website, April, 12, 2012). Suppose we take a sample of employees from the manufacturing industry to see if the mean hourly wage differs from the reported mean of $24.57 for the goods-producing industries. b. Suppose a sample of 30 employees from the manufacturing industry showed a sample mean of $23.89 per hour. Assume a population standard deviation of $2.40 per hour and compute the p-value. Round your answer to four decimal places. c. With alpha =0.05 as the level of significance, what is your conclusion? The input in the box below will not be graded, but may be reviewed and considered by your instructor.

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