You are conducting a multinomial Goodness of Fit hypothesis test for the claim that the 4 categoriesoccur with the following frequencies:H.:PA = 0.15; pB = 0.3; pc = 0.4; pp = 0.15Complete the table. Report all answers accurate to three decimal places.ExpectedFrequency FrequencyObservedCategory9.15466.What is the chi-square test-statistic for this data?x =What is the P-Value?P-Value =For significance level alpha 0.01,What would be the conclusion of this hypothesis test?O Reject the Null HypothesisNOVétv23DDF9F10F1F6F7F8&89C.

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You are conducting a multinomial Goodness of Fit hypothesis test for the claim that the 4 categories occur with the following frequencies: H.:PA = 0.15; pB = 0.3; pc = 0.4; pp = 0.15 Complete the table. Report all answers accurate to three decimal places. Observed Expected Frequency Frequency Category A 9. 15 46 What is the chi-square test-statistic for this data? x² = What is the P-Value? P-Value =

You are conducting a multinomial Goodness of Fit hypothesis test for the claim that the 4 categories occur with the following frequencies: H.:PA = 0.15; pB = 0.3; pc = 0.4; pp = 0.15 Complete the table. Report all answers accurate to three decimal places. Observed Expected Frequency Frequency Category A 9. 15 46 What is the chi-square test-statistic for this data? x² = What is the P-Value? P-Value =

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are conducting a multinomial Goodness of Fit hypothesis test for the claim that the 4 categories occur with the following frequencies: A B C D Complete the table. Report all answers accurate to three decimal places. Category Observed Expected Frequency Frequency 23 = 22 20 22 Ho: PA= 0.15; PB What is the chi-square test-statistic for this data? What is the P-Value? P-Value = = 0.3; Pc' = 0.4; For significance level alpha 0.1, What would be the conclusion of this hypothesis test? O Fail to reject the Null Hypothesis Reject the Null Hypothesis PD = 0.15