You are asked to calibrate a 25.00 mL volumetric pipet. You determine the temperature of your distilled water is exactly 30 degrees celsius. You carefully determined the mass of a clean, dry beaker and found it was 60.1703 g. You pulled the water up to the mark and transferred this to the beaker and found that the new mass was 85.2263 g. What is the actualy volume of the pipet? I tried answering the question above by doing 85.2263 - 60.1703 = 25.056 g I then used 25.056 and multipled it with .995646 (which is the density of water at 30 degrees celsius I believe) The answer I got is 24.947 I am not sure if I am just doing the problem wrong or if it is simply my signifcant figures that are off? Please help :))
You are asked to calibrate a 25.00 mL volumetric pipet. You determine the temperature of your distilled water is exactly 30 degrees celsius. You carefully determined the mass of a clean, dry beaker and found it was 60.1703 g. You pulled the water up to the mark and transferred this to the beaker and found that the new mass was 85.2263 g. What is the actualy volume of the pipet? I tried answering the question above by doing 85.2263 - 60.1703 = 25.056 g I then used 25.056 and multipled it with .995646 (which is the density of water at 30 degrees celsius I believe) The answer I got is 24.947 I am not sure if I am just doing the problem wrong or if it is simply my signifcant figures that are off? Please help :))
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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You are asked to calibrate a 25.00 mL volumetric pipet. You determine the temperature of your distilled water is exactly 30 degrees celsius. You carefully determined the mass of a clean, dry beaker and found it was 60.1703 g. You pulled the water up to the mark and transferred this to the beaker and found that the new mass was 85.2263 g. What is the actualy volume of the pipet?
I tried answering the question above by doing 85.2263 - 60.1703 = 25.056 g
I then used 25.056 and multipled it with .995646 (which is the density of water at 30 degrees celsius I believe)
The answer I got is 24.947
I am not sure if I am just doing the problem wrong or if it is simply my signifcant figures that are off? Please help :))
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