The equation x - 16x³ = 0 O (A) has two (and only two) distinct real roots O (B) has four (and only four) distinct real roots O (C) has nine distinct real roots O (D) has three (and only three) distinct real roots O(E) cannot be solved
The equation x - 16x³ = 0 O (A) has two (and only two) distinct real roots O (B) has four (and only four) distinct real roots O (C) has nine distinct real roots O (D) has three (and only three) distinct real roots O(E) cannot be solved
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter4: Polynomial And Rational Functions
Section4.5: Zeros Of Polynomial Functions
Problem 74E
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Power of 25/3 and 1/3
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The equation x - 16x = 0
O (A) has two (and only two) distinct real roots
O(B) has four (and only four) distinct real roots
O (C) has nine distinct real roots
O (D) has three (and only three) distinct real roots
O (E) cannot be solved
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The equation x - 16x = 0
O (A) has two (and only two) distinct real roots
O(B) has four (and only four) distinct real roots
O (C) has nine distinct real roots
O (D) has three (and only three) distinct real roots
O (E) cannot be solved
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Follow-up Questions
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Follow-up Question
yes but the negative radical 2 is not a real number and in the options they are asking for a real distinct solution
![3:38
Solutions Solving Steps
The expressionIS UNTUTTined in the set oricar
numbers
Simplify
Undefined
0=0
0=0
x#-√3
0=0
0=0
Since the expression is undefined in the
set of real numbers, x= -√3 is not a
solution of the equation
x= -√3
x=0
x = √3
The equation has 2 solutions
Solution
x₁ = 0₁x₂ = √3
0,
Alt
ive Form
.4G
Next Step
5
X₁−u, X₂~1,73200
X](https://content.bartleby.com/qna-images/question/6099d21a-e15a-47f8-adbb-0c871c33581f/2089cf75-bfa9-4939-9fc0-9eb8a58da27e/vf3czua_thumbnail.jpeg)
Transcribed Image Text:3:38
Solutions Solving Steps
The expressionIS UNTUTTined in the set oricar
numbers
Simplify
Undefined
0=0
0=0
x#-√3
0=0
0=0
Since the expression is undefined in the
set of real numbers, x= -√3 is not a
solution of the equation
x= -√3
x=0
x = √3
The equation has 2 solutions
Solution
x₁ = 0₁x₂ = √3
0,
Alt
ive Form
.4G
Next Step
5
X₁−u, X₂~1,73200
X
Solution
Follow-up Question
yes i understand how to solve it and i know we get 3 values but dont you automatically reject the negative because the exponents are fractions?
Solution
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