**Educational Website Explanation**### Table: Age Distribution and Location of BuffaloThis table presents the age distribution and location of a random sample of 166 buffalo in a national park.#### Data Breakdown:- **Age Categories**: Calf, Yearling, Adult- **Locations**: - Lamar District - Nez Perce District - Firehole District| Age | Lamar District | Nez Perce District | Firehole District | Row Total ||----------|----------------|--------------------|-------------------|-----------|| Calf | 12 | 13 | 16 | 41 || Yearling | 12 | 11 | 10 | 33 || Adult | 31 | 27 | 34 | 92 || Column Total | 55 | 51 | 60 | 166 |### Chi-Square Test for Independence1. **What is the level of significance?** - The level of significance is 0.05.2. **Null and Alternative Hypotheses:** - \( H_0 \): Age distribution and location are independent. - \( H_a \): Age distribution and location are not independent.3. **Chi-Square Statistic Calculation:** - Determine the expected frequencies for each category combination. - Calculate the chi-square statistic by comparing observed frequencies to expected frequencies.4. **Expected Frequency Check:** - Are all the expected frequencies greater than 5? - Options: Yes, No5. **Sampling Distribution and Degrees of Freedom:** - Sampling distribution: Chi-square - Degrees of freedom are calculated as: (Number of rows - 1) * (Number of columns - 1)6. **P-value Estimation:** - Estimates based on ranges, e.g., \( 0.010 < \text{P-value} < 0.050 \), etc.7. **Hypothesis Testing Decision:** - Depending on the p-value, determine whether to reject or fail to reject \( H_0 \).8. **Conclusion Interpretation:** - At the 5% level of significance, a conclusion is drawn about the independence of age distribution and location based on whether \( H_0 \) is rejected or not.By analyzing this data using a chi-square test, researchers can

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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One-way ANOVAPart 1. One-Way Analysis of Variance (ANOVA)1. Null Hypothesis (just in words): 2. Alternative Hypothesis (just in words). 3. Is the data violating one of the ANOVA assumptions? _______________
11. Hypothesis Test of Equal Variances. Test the given claim. Use a significance level of a = 0.05 and assume that all populations are normally distributed. Claim: The treatment population and the placebo population have different variances. n = 16, x = 21.33, s = 0.80 n = 41, x = 25.34, s = 0.40 Treatment group : Placebo group :
Mean 1001 206 Levene's Test for Equality of Variances Sig. 15.578 <.001 .510 1.402 df Sig. (2-tailed) 1205 .014 261.832 035 -3.168 -3.168 Std. Error Difference 3. Do Whites spend a significantly different amount of time on the internet (WWWHR) than Blacks? Group Statistics Std. Error Race of respondent N Std. Deviation Mean Www.hours per week WHITE 13.29) (16.124) BLACK 16.46 20.120 Independent Samples Test t-test for Equality of Means Mean t Difference Www hours per week -2.455 Equal variances assumed -2.124 Equal variances not assumed 1.291 1.492 95% Confidence Interval of the Difference Lower Upper -5.701 -6.106 -.636 -.231
An elementary school teacher is interested in knowing if there is a significant difference in the average reading speed of fifth-grade boys and girls. She randomly selects 36 fifth grades boys and 36 fifth grade girls for the study. Each student is given several pages of the same book to read and the time it takes them to complete the reading is recorded in minutes. Boys Girls Sample Size 36 36 Sample Mean reading speed (in minutes) 11 12 Population Variance 3 2 The p-value is a. 0.156 b. 0.0037 c. 0.336 d. 0.238
Test the claim about the population mean, at the given level of significance using the given sample statistics. Claim 50, a0.04, 351. Sample statistics i 48 2, n- 72 Identily the null and alternative hypotheses. Choose the corect answer below OA. H: p 50 H, p50 OB. H: 50 H, pe50 OC. Họ p> 50 D. H 50 H, 50 OE Ho 50 H, 50 OF. H: p= 50 Calculate the standardized test statistic The standardized test statistic is -4.35. (Round to two decimal places as needed) Determine the critical value(s) Select the corect choice below and flin the answer box to complete your cholce. (Round to two decimal places as needed) OA. The critical value is O B. The critical values are
Which statement is NOT a possible statement for an alternative hypothesis? O population characteristic = hypothesized value O population characteristic hypothesized value O population characteristic hypothesized value #
Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…
We would like to investigate if there is a difference in mean coffee consumption frequency between students at Rutgers, Princeton, and the University of Michigan. What test would we likely conduct? Independent samples t-test One Sample z-test Paired samples t-test One Way ANOVA
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The following table shows ceremonial ranking and type of pottery sherd for a random sample of 434 sherds at an archaeological location. Decorated Jar Sherds (Noncooking) Ceremonial Ranking Cooking Jar Sherds Row Total A 89 46 135 89 56 145 74 80 154 Column Total 252 182 434 n USE SALT Use a chi-square test to determine if ceremonial ranking and pottery type are independent at the 0.05 level of significance. (a) What is the level of significance? State the null and alternate hypotheses. O Họ: Ceremonial ranking and pottery type are not independent. H,: Ceremonial ranking and pottery type are independent. O Ho: Ceremonial ranking and pottery type are independent. H,: Ceremonial ranking and pottery type are independent. O Ho: Ceremonial ranking and pottery type are not independent. H,: Ceremonial ranking and pottery type are not independent. O Ho: Ceremonial ranking and pottery type are independent. H,: Ceremonial ranking and pottery type are not independent. (b) Find the value of the…
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The accompanying table lists pulse rates. Use a 0.05 significance level and apply the methods of two-way analysis of variance. What is the conclusion? Click on the icon to view the data table. C State the null and alternative hypotheses in the test for the effect of an interaction between row and column factors. Ho: There is no interaction between gender and age. H₁: There is an interaction between gender and age. What is the value of the test statistic for this test? F = 3.32 (Round to two decimal places as needed.) What is the corresponding P-value of the test statistic, F, for this P-value= (Round to three decimal places as needed.) Pulse Rates for Gender and Age Over 30 Years of Age Under 30 Years of Age Female 78 103 78 63 61 98 81 98 91 95 77 75 73 65 71 78 61 71 74 55 Female Male 60 81 56 69 68 74 75 68 63 56 46 70 61 65 91 80 59 58 64 59 Male D X

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