The plastic distorts as shown by the dashed lines. (Figure 1)The dimensions are L = 470 mm, H = 395 mm,d₁ = 2 mm, d₂ = 4 mm, d3 = 14 mm, d4 = 9 mm,2 mm, and do4 mmd5FigureHLBdzd1 of 1Part ADetermine the shear strain Yry at corner C.Express your answer to three significant figures and include appropriate units.(YC)zy =SubmitPart BμA(YD)zy =ValueRequest AnswerDetermine the shear strain Yzy at corner D.Express your answer to three significant figures and include appropriate units.μAValueUnitsSubmit Request Answer?Units?

Answered: Image /qna-images/answer/9b62a104-40ed-411a-8b26-1830a98acac5.jpg

Answered: (YC)zy = Submit Part B Value (YD)zy =…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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In a volume element with dimensions dx, dy, dz the negatíve y-face has a 2 MPa stress in the positivex-direction, a 3 MPa stress in the negative z-direction, and a 4 MPa stress in the negative y-direction. Which of the following describes the stresses per elasticity convention? Oy = 4 MPa Oyr = -2 MPa Oyz = 3 MPa Oy = -4 MPa Oye = 2 MPa Oyz = -3 MPa Oy = 3 MPa Oye = -4 MPa Oyz = 2 MPa =4 MPa Oyr = 2 MPa Oyz = -3 MPa
This is my ID :201903062
Determine the state of stress of a beam at the point shown in Figure 2 to represent: a) the principal stresses; b) the maximum in-plane shear stress and the associated average normal stress. c) For each of the two cases mentioned in (a) and (b), determine the corresponding orientation of the element with respect to the original element shown and sketch the results relative to the longitudinal axis of the beam. Please show the full working to provide sufficient information for the sketching to be complete. 15MPa Figure 2 20° 50MPa
Learning Goal: A material is homogenous and isotropic when it has a modulus of elasticity that does not vary with direction and it has uniform properties throughout. When a point in a material is subjected to only normal stresses in three dimensions, but they are not necessarily equal, the state is called triaxial stress. When the response of the material is linear elastic, the strains along the three axes can be calculated using a generalized form of Hooke's law. Each strain depends on all three stresses because of the Poisson effect. €1 Figure 1 [0₂ - V (O₂ +0₂)] a 1 of 1 A cube is subjected to stresses with magnitudes a = 16 MPa, b = 26 MPa, and c = 5 MPa (Figure 1). What is the strain in the y-direction? Let E = 200 GPa and v= 0.26. Express your answer to three significant figures. ► View Available Hint(s) Submit VE ΑΣΦ Part B - Change in volume f change in volume = vec The cube from Part A originally has side length 3.2 cm . What is the change in volume of the cube under the given…
The grains of wood in the board make an angle of 20° with the horizontal as shown. Using Mohr's circle, determine the normal and shear stresses that act perpendicular and parallel to the grains if the board is subjected to an axial load of P = 300 N. (Figure 1) Figure -300 mm $20⁰ 25 mm 60 mm P
Learning Goal: The rectangular cross section ABCD shown below has a circular cutout of diameter d = 50.0 mm through its center. The member is subjected to two externally applied moments M₁ = 6.0 kNm and M₂ =17.0 kNm at angles 0₁ = 35.0 degrees from the y axis in the yz plane and 02 = 25.0 degrees from the z axis in the yz plane, respectively. The rectangular cross section has a height of h = 290.0 mm and a width of w = 125.0 mm M₁ 8₁ NE d B 78₂ W 2
I have been stuck on this problem for while thar area is 779.1 mm^2 sigma_x is 120.6497159 sigma_y is 0 and tau_xy is 0. Beta is 20 degrees
Determine the resulting maximum value of the normal stress. Specify the orientation of the plane on which these maximum values occur. **The answer is tensile stress is 0 ksi at 90 degrees. **The answer is compressive stress is 7 ksi at 0 degrees. Can you explain how that is? This was my thought process: I know that tensile would be zero because the force P is actually going inwards and not outwards. I know that means that there would be a compressive force. I am confused on the angles, how is a tensile force going 90 degress if there technically is no force in the tensile direction. And how is there a compressive force at 90 degrees if there is a stress? thank you!

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(YC)zy = Submit Part B Value (YD)zy = Request Answer Determine the shear strain Yzy at corner D. Express your answer to three significant figures and include appropria μA Units Value Units ?