of the plane on which these maximum values occur. **The answer is tensile stress is 0 ksi at 90 degrees. **The answer is compressive stress is 7 ksi at 0 degrees. Can you explain how that is? This was my thought process: I know that tensile would be zero because the force P is actually going inwards and not outwards. I know that means that there would be a compressive force. I am confused on the angles, how is a tensile force going 90 degress if there technically is no force in the tensile direction. And how is there a compressive force at 90 degrees if there is a stress? thank you!
Determine the resulting maximum value of the normal stress. Specify the orientation of the plane on which these maximum values occur.
**The answer is tensile stress is 0 ksi at 90 degrees.
**The answer is compressive stress is 7 ksi at 0 degrees.
Can you explain how that is? This was my thought process: I know that tensile would be zero because the force P is actually going inwards and not outwards. I know that means that there would be a compressive force. I am confused on the angles, how is a tensile force going 90 degress if there technically is no force in the tensile direction. And how is there a compressive force at 90 degrees if there is a stress? thank you!
![A 252-kip concentric load P is applied to the granite block shown.
P
6 in.
6 in.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa1389f7f-60f2-476a-92c5-edfb12b791f4%2Ffd64b152-6d5e-4c0b-8579-45e33b22e473%2F8vuye1_processed.png&w=3840&q=75)
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Given data
Force p = 252 kips
Area = 6 × 6 in ^2
Find the stress and angle
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