Y4(t) = ¿et is a particular solution of y" – y = 2e3t. The general solution of /" – y = 2e3t is y5(t) = C1e=t + Cze' + že.
Y4(t) = ¿et is a particular solution of y" – y = 2e3t. The general solution of /" – y = 2e3t is y5(t) = C1e=t + Cze' + že.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Are any of these statements true or false?
Transcribed Image Text:Y4(t) = 4e*
,3t
is a
particular solution of
y" – y = 2e3t.
The general solution
of
y" – y = 2et is y5(t) = C1e¬t + C2e' + žet.
Transcribed Image Text:Note: C1 and C2
are arbitrary
constants.
Y1(t) = e=t and y2(t) = e*
are independent
solutions of
y" – y = 0.
||
The complementary
function of
y" – y = 2et is y3(t) = C1e¬t + C2e'.
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