Y=1/4x^4-3/2x^2 gjej monotonin dhe nderto tabelen e saj

Q1 PART 1 There are several bitwise operators to help manipulate bits: · & - Operates on the corresponding bits of two strings of bits. The result is a 1 if both bits were 1, O if not. •|- Operates on the corresponding bits of two strings of bits. The result is a 1 if either bit was 1, O if not. .^ - Operates on the corresponding bits of two strings of bits. The result is a 1 if only one bit was 1, 0 if not. .» (number) - Operates on one string of bits. Shifts all bits to the right equivalent to the number provided. .< (number) - Operates on one string of bits. Shifts all bits to the left equivalent to the number provided. .N- Operates on one string of bits. Inverses all of the bits. Consider variable string1 = Ox12345678 and variable mask = OxC Fill in the missing value (???) by inputting what it should be in the Solutions boxes adjacent to the respective Task below. Each Task is distinct so earlier tasks have no bearing on the following ones (updating string1 will only be for that…

9121 Q/ convert thise quation below For coding in visual basic -=| In(Q) log (x) Y= 2 2 * Cos F T SAA

What is the decimal equivalent of the hexadecimal number 1C9F?       ______________

Question  ADD’ing 1FH and 20H will result in which of the following hexadecimal numbers? Select one: a. 0 b. 16 c. 63 d. 3F e. 45 Full explainthe  this question very fast solution sent me step by step Don't ignore any part all part work u  Text typing work only not allow paper work

What is the maximum possible length of an identifier? O Identifiers can be any length O depends on the interpreter/compiler O A fixed number based on the python version O it depends on if the machine is 32 or 64 bits

Make this into a flowchart

E = D'C'B'A' + D'C'BA' + D'C'BA + D'CB'A + D'CBA' + D'CBA + DC'B'A' + DC'B'A F = D'C'B'A'+ D'CB'A' + D'CB'A + D'CBA' + DC'B'A' + DC'B'A G = D'C'B'A' + D'C'B'A + D'C'BA' + D'C'BA + D'CB'A' + D'CBA + DC'B'A' + DC'B'A H = D'C'BA' + D'C'BA + D'CB'A' + D'CB'A + D'CBA' + DC'B'A' + DC'B'A I = D'C'B'A' + D'C'BA' + D'CBA' + DC'B'A' J = D'C'B'A' + D'C'B'A + D'C'BA + D'CB'A' + D'CB'A +D'CBA' + D'CBA + DC'B'A' + DC'B'A K = D'C'B'A' + D'C'BA' + D'C'BA + D'CB'A + D'CBA' + DC'B'A'

y = 0 b' so 00 s2 10 a b' y 0 b b Fill in next state bits. 'b' s1 01 y 1 || so s1 s2 Unused pl po b nl no y 0 0 0 0 0 1 0 00 0 0 1 0 1 0 1 1 1 1 0 1 1 1 100 000 1 1 1 0 0 1 1 0 000 000

use C programming stdio.h enter a number:5 output : 5,10,15,20,25,20,15,10,5  enter a number :3 output : 3,6,9,6,3 * TERMINATION ______________________________________________________________________ second PROBLEM C PROGRAMMING STDIO.H    N1 N2 OUTPUT 0 0 GOT7 POSITIVE EVEN  POSTIVE EVEN N1+N2 POSITIVE ODD POSITIVE ODD N1 x N2 NEGATIVE EVEN NEGATIVE EVEN MARK TUAN NEGATIVE EVEN NEGATIVE ODD JACKSON WANG       WITH TERMINATION ___________________________________________________________________________ 3RD PROBLEM USING C PROGRAMMING STDIO.H     the 1ST INPUT is 5  2ND input 13  output : 5, 8 ,13 *TERMINATION   ---------------------------------------------------------------------- last question  c programming stdio.h I think the problem starts before the nested if switch because at the end of the code it should output the result of sales = quantity * price and change = payment - total amount and asking quantity and Payment #include<stdio.h> main() { int…